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sergiy2304 [10]

3 years ago

11

A motorboat accelerates uniformly from a velocity of 10.5 m/s to the west to a velocity of 6.5 m/s to the west. If its accelerat

ion was 4.5 m/s2 to the east, how far did it travel during the acceleration

1 answer:

BlackZzzverrR [31]3 years ago

3 0

Answer:

7.4m ............................

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. A weather balloon is inflated to a volume of 2.2 x 103 L with 37.4 g of helium. What is the density of helium in grams per lit

Margarita [4]

That is the mst best eway to find its solution.
37.4/2.2*10^3 = 0.017 gm/liter or 1.7*10^-2
so we conclude that option b is sorrect

6 0

4 years ago

A metal can containing condensed mushroom soup has mass 215 g, height 10.8 cm, and diameter 6.38 cm. It is placed at rest on its

s344n2d4d5 [400]

Answer:

Part a)

Moment of inertia of the cylinder is given as

$I = 1.21 \times 10^{-4} kg m^2$

Part B)

Height of the cylinder is of no use here to calculate the inertia

Part C)

Since we don't know about the viscosity data of the soup inside the cylinder so we can't say directly about the moment of inertia of the cylinder as $I = 1/2 mR^2$

Explanation:

As we know that the inclined plane is of length L = 3 m

and its inclination is given as 25 degree

so we know that acceleration of center of mass of the cylinder is constant so we will have

$v_f^2 = v_i^2 + 2 a L$

so we have

$v_f^2 = 0 + 2a(3)$

now we know that

$v_{avg} = \frac{L}{t} = \frac{v_f + v_i}{2}$

$\frac{3}{1.50} = \frac{v_f + 0}{2}$

$v_f = 4 m/s$

Now we have know that final speed of the cylinder due to pure rolling is given as

$v_f = \sqrt{\frac{2gH}{1 + \frac{I}{mR^2}}}$

$4 = \sqrt{\frac{2(9.81)(3 sin25)}{1 + \frac{I}{0.215(0.0319)^2}}}$

$I = 1.21 \times 10^[-4} kg m^2$

Part B)

Height of the cylinder is of no use here to calculate the inertia

Part C)

Since we don't know about the viscosity data of the soup inside the cylinder so we can't say directly about the moment of inertia of the cylinder as $I = 1/2 mR^2$

8 0

3 years ago

Most geologists believe that the dinosaurs became extinct 65 million years ago when a large comet or asteroid struck the earth,

Alex17521 [72]

Answer:

A) 1.67 x 10 ⁻⁶ m/s

B)5.59 x $10^-^9$ %

Explanation:

A)

Given:

d = 5.0 km,

mₐ = 2.5 x $10^1^4$ kg

u₁ = 4.0 x 10⁴ m/s

$m_n$ = 5.98 x 10 ²⁴ kg

Solve using kinetic conserved energy

mₐ x u₁ + $m_n$ x u₂ = uₓ x (mₐ + $m_n$ )

(2.5 x $10^1^4$ ) (4.0 x 10⁴ )+ (5.98 x 10 ²⁴ )(0) = uₓ x (2.5 x $10^1^4$ + 5.98 x 10 ²⁴ )

uₓ = ( 2.5 x $10^1^4$ x 4.0 x 10⁴ ) / (2.5 x $10^1^4$ + 5.98 x 10 ²⁴ )

uₓ = 1.67 x 10 ⁻⁶ m/s

B) Assuming earth radius as a R = 1.5 x 10 ¹¹ m

t = 365 days x 24 hr / 1 day x 60 minute / 1 hr x 60s / 1 minute = 31536000 s

t = 31536000 s

D = 2 π R = 2 π( 1.5 x 10 ¹¹ )

D = 9.4247 x 10 ¹¹ m

u₂ = D / t = 9.4247 x 10 ¹¹ / 31536000

u₂ = 29885.775 m/s

% = ( 1.67 x 10 ⁻⁶ m/s ) / (29885.775 m/s) x 100

% = 5.59 x $10^-^9$ %

5 0

3 years ago

If a person wanted to calculate how much kinetic energy an object has, the equation they would use would be: Question 2 options:

nexus9112 [7]

Answer: $KE=\frac{1}{2}mv^{2}$

Explanation:

Kinetic Energy is the energy a particle, body or object possesses due to its movement and is mathematically defined as:

$KE=\frac{1}{2}mv^{2}$

Where:

$m$ is the mass of the body

$v$ is the velocity of the body

So, if we want to calculate the kinetic energy $KE$ of an object, we have to use the equation given above.

8 0

3 years ago

True or False: Cooler objects always have more thermal energy than warmer objects.

tensa zangetsu [6.8K]

False

Because you can see using a thermal camera I guess

3 0

3 years ago