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Lapatulllka [165]
3 years ago
6

10. 5.8 - (0.25 X 1.5) Just need 3 4 and 5 where 3.852 is thanks

Mathematics
1 answer:
harina [27]3 years ago
7 0

Answer:

HOPE it will be right... Good luck

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5d×(d-4)

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4 years ago
The longest straw that can fit inside a 5-inch cylindrical cup, if the straw is placed at an angle in the cup, is 6
Softa [21]

Answer:

yo i do primavara to imma do 3.9

Step-by-step explanation:

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8 0
3 years ago
Expanded notation on algebra<br> 24 x 12 x 12
Delvig [45]

Answer:

3456

Step-by-step explanation:

24x12=288

288x12=3456

4 0
3 years ago
based on the simulation, what is the probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to
Triss [41]

Using the binomial distribution, supposing that 0.3 of the callers have to wait more than 8 minutes to have their calls answered, it is found that there is a 0.3828 = 38.28% probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to have their calls answered.

For each caller, there are only two possible outcomes, either they have to wait more than 8 minutes to have their calls answered, or they do not. The probability of a caller having to wait more than 8 minutes is independent of any other caller, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 10 callers, hence n = 10
  • Suppose that 0.3 of them have to wait more than 8 minutes, hence p = 0.3

The probability that <u>at most 2</u> of the next 10 callers will have to wait more than 8 minutes is:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.3)^{0}.(0.7)^{10} = 0.0282

P(X = 1) = C_{10,1}.(0.3)^{1}.(0.7)^{9} = 0.1211

P(X = 2) = C_{10,2}.(0.3)^{2}.(0.7)^{8} = 0.2335

Then:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0282 + 0.1211 + 0.2335 = 0.3828

0.3828 = 38.28% probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to have their calls answered.

A similar problem is given at brainly.com/question/25537909

3 0
3 years ago
Joshua can purchase tile at one store for $0.99 per tile but he he will have to rent a tile saw for $25. At another store he can
Debora [2.8K]

Answer:

The number of tile for which the cost is same route to nearest tile is 49 .

Step-by-step explanation:

Given as :

The cost which Joshua will pay for tile at one store = $ 0.99 per tile + $ 25 for tile saw

The  cost which Joshua will pay for tile at another store = $ 1.50 per tile only

Let The number of tile for which the cost is same route to nearest tile = n

So, According to question

$ 0.99 × number of tile + $ 25 = $ 1.50 × number of tile

or, $ 0.99 × n + $ 25 = $ 1.50 × n

or, $ 1.50 × n - $ 0.99 × n = $ 25

I.e 0.51 × n = $ 25

∴  n = \frac{25}{0.51}

I.e n = 49.01 ≈ 49

So, The number of tile for which the cost is same route to nearest tile = n = 49

Hence The number of tile for which the cost is same route to nearest tile is 49 . Answer

5 0
3 years ago
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