Answer:
s = 6 m
Step-by-step explanation:
The value of the velocity v is given as:
m/s
To find s, we have to integrate and apply the initial values of s = o when t = 0:
When t = π/2, s will be:
s = -3cos(2 * π/2) + 3
s = -3cos(π) + 3
s = -3(-1) + 3
s = 3 + 3
s = 6 m
Answer:
We can think that the line of the kite is the hypotenuse of a triangle rectangle, and the altitude is one of the cathetus of the triangle.
And we know that it makes an angle of 65° with the horizontal (i guess this is measured between the hypotenuse and the horizontal adjacent to the kite.
This angle is complementary to the top angle of our triangle rectangle, such that A + 65° = 90°
A = 90° - 65° = 25°
Then the altitude of the kite is the adjacent cathetus to this angle.
We can use the relation:
sin(A) = Adjacent cathetus/hypotenuse.
Sin(25°) = X/350ft
Sin(25°)*350ft = X = 147.9m
Answer:
The correct answer is A: Interquartile range
Step-by-step explanation:
Just took the test and this was the correct answer
answer:
32
Step-by-step explanation:
I’d say it’s between B and D
