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Ann [662]
3 years ago
15

A 36.41-g sample of calcium carbonate (CaC O 3 )

Chemistry
1 answer:
Lunna [17]3 years ago
7 0
M(O) = m(CaCO₃) - m(Ca) - m(C).
m(O) = 36.41 g - 14.58 g - 4.36 g.
m(O) = 17.47 g.
ω(Ca) = m(Ca) ÷ m(CaCO₃) · 100%.
ω(Ca) = 14.58 g ÷ 36.41 g · 100%.
ω(Ca) = 40 %; mass percent of calcium.
ω(C) = m(C) ÷ m(CaCO₃) · 100%.
ω(C) = 4.36 g ÷ 36.41 g · 100%
ω(C) = 12%; mass percent of carbon.
ω(O) = 100% - ω(Ca) - ω(C).
ω(O) = 100% - 40% - 12%.
ω(O) = 48%; mass percent of oxygen.
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3 years ago
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What is the volume of a 5.30g piece of aluminum? The density for aluminum is 2.70gmL.
Blizzard [7]

The volume of the piece of aluminum is 1.96 mL

Explanation:

Density is the relationship of the mass of a substance and its volume.

In this case, the mass of aluminum is 5.30 g and the density is 2.70 g/mL

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3 years ago
When comparing Potassium (K) and Calcium (Ca) you must compare?
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8 0
2 years ago
7944/0.024 = _______ give the answer to the correct number of significant figures?
In-s [12.5K]

Answer:

330,000

Explanation:

Since there are only 2 significant figures in 0.024 ( and 0.024 is the number with the least number of significant numbers), the answer is 330,000, not 331,000.

5 0
3 years ago
The molar mass of H2O is 18.01 g/mol. The molar mass of O2 is 32.00 g/mol. What mass of H2O, ins grams, must react to produce 50
Ivan

Answer:

56.28 g

Explanation:

First change the grams of oxygen to moles.

(50.00 g)/(32.00 g/mol) = 1.5625 mol O₂

You have to use stoichiometry for the next part.  Looking at the equation, you can see that for every 2 moles of H₂O, 1 mole of O₂ is produced.  Convert from moles of O₂ to moles of H₂O using this relation.

(1.5625 mol O₂) × (2 mol H₂O/1 mol O₂) = 3.125 mol H₂O

Now convert moles of H₂O to grams.

(3.125 mol) × (18.01 g/mol) = 56.28125 g

Convert to significant figures.

56.28125 ≈ 56.28

5 0
3 years ago
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