Answer: ~54.54 units squared, or 25*pi - 24
Step-by-step explanation:
To find this, we need to find both the area of the triangle and circle, and then subtract the area of the triangle from the area of the circle.
Area of triangle: ![A = (bh)/2](https://tex.z-dn.net/?f=A%20%3D%20%28bh%29%2F2)
Area of circle: ![A = \pi r^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cpi%20r%5E2)
To find the radius, we first need to find the hypotenuse of the triangle, which happens to be the diameter of the circle.
Pythagorean Theorem:
, where a and b are sides and c is the hypotenuse.
6^2 + 8^2 = c^2
36 + 64 = 100, c = 10
Knowing that the diameter is 10, we also know that the radius is 5.
Area of the circle with a radius of 5 is 25*pi, or 78.54~
Area of the triangle with side lengths of 6 and 8 is 24.
78.54 - 24 = 54.54 units squared.
9:
r
15.5 (not the one with the line under it i just couldnt find the one that didnt have the line under it)
for the graph, put 16 on the right side and label the lines right to left 16 15.5 14 14.5 etc. Put an open circle on the 15.5 line. then make an arrow pointing to the left.
10:
80
p+64
This is because she needs 80 points OR MORE and (p represents the points) she already has 64. She needs 80 to be less than or equal to the amount of points earned.
The solution is 16
p because 80-64=16 and p is needs to be greater than or equal to 16
Answer: 2![4\sqrt{x} 4](https://tex.z-dn.net/?f=4%5Csqrt%7Bx%7D%204)
Step-by-step explanation:
Answer:
C. g(x) = 3![x^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D)
Step-by-step explanation:
f(1) = 1 and g(1) = 3
g(1) is 3 times more than f(1)
So, g(x) = 3![x^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D)
Answer: b) (2m³ - 4p⁵)(2m³ + 4p⁵)
<u>Step-by-step explanation:</u>
Use the difference of a square formula: a² - b² = (a - b)(a + b)
![4m^6 - 16p^{10}\\\bullet a) \sqrt{4m^6}=2m^3\\\bullet b)\sqrt{16p^{10}}=4p^5](https://tex.z-dn.net/?f=4m%5E6%20-%2016p%5E%7B10%7D%5C%5C%5Cbullet%20a%29%20%5Csqrt%7B4m%5E6%7D%3D2m%5E3%5C%5C%5Cbullet%20b%29%5Csqrt%7B16p%5E%7B10%7D%7D%3D4p%5E5)
(2m³)² - (4p⁵)² = (2m³ - 4p⁵)(2m³ + 4p⁵)