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3 years ago

Evaluate the function: f(x)=4x−1, find f(9)

Mathematics

1 answer:

Eddi Din [679]3 years ago

3 0

Answer:

f(9) = 35

Step-by-step explanation:

To solve this, you can take 9 and replace both x's with it and then complete the equation;

f(x) = 4x - 1

f(9) = 4(9) - 1

f(9) = 36 - 1

f(9) = 35

Hope this helps!

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Jamison graphs the function ƒ(x) = x4 − x3 − 19x2 − x − 20 and sees two zeros: −4 and 5. Since this is a polynomial of degree 4

Art [367]

We are given polynomial function f(x)= $x^4-x^3-19x^2-x-20$

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Let us write some steps to factor the given polynomial.

Let us take above factor (x+4) first.

On factoring (x+4) we get factors

$x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x^3-5x^2+x-5\right)$

$\mathrm{:Let \ us \ factor}\:x^3-5x^2+x-5 \ now.$

Grouping

$=\left(x^3-5x^2\right)+\left(x-5\right)$

Factoring out gcf from each group, we get

$=x^2\left(x-5\right)+\left(x-5\right)$

$=\left(x-5\right)\left(x^2+1\right)$

So, the final factored form of given polynomial will be

$x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x-5\right)\left(x^2+1\right)$

For first to factors (x+4) and (x-5) we have given roots: -4 and 5.

Let us find the root of third factor we got.

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Subtracting both sides by 1.

x^2 = - 1.

On taking square root on both sides, we get a square root(-1)

$x=\sqrt{-1}=$ + i and -i.

Those are imaginary solutions.

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4 years ago

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Juli2301 [7.4K]

$(2-8)/1$

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