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Masteriza [31]
3 years ago
8

Urgent plz no one helps me!!!!!!!!!!!!

Mathematics
1 answer:
Rudik [331]3 years ago
8 0
A $2.20+$2.40x= >$9.00

B Patricia can buy 2 Pou d of potatos
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If the silver accounts for 84% of the bar's weight, what is the weight of the silver?
lidiya [134]
Weight=8.15 ounces
silver=84%of the total weight
silver=(84/100)×8.15 ounces
silver= 0.84×8.15 ounces
silver=7.5795 ounces
silver=7.580 ounces (rounded to nearest thousandth)
8 0
2 years ago
Length of a rectangle is four times its width. If the perimeter is 100 m, what is the area in square cm?
melisa1 [442]

Set the width to be x. Thus, the length is 4x.

The perimeter is 2(x+4x)=100, so x=10.

Plugging in x=10, you get that 4x=40.

So, the area of the rectangle is 400 m^2.

Because there are 100 centimeters in a meter and you are asking for area, you must multiply by 100^2 to get 4000000 cm^2.


6 0
3 years ago
Brian, Kelsy, and Geoff each have a remote-controlled car. they simultaneously started their cars and drove them in a straight l
Margarita [4]

Answer: where’s the photo/attachment??

Step-by-step explanation:

8 0
3 years ago
-1/2 (−4n+6)+3n=47 solve n=?
Sidana [21]

Answer:

N:10

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The tensile strength of a metal part is normally distributed with mean 40 pounds and standard deviation 5 pounds. If 50,000 part
nalin [4]

Answer:

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

7933 parts

b) How many would have a tensile strength in excess of 48 pounds?

2739.95 parts

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

z = (x-μ)/σ

x = 35 μ = 40 , σ = 5

z = 35 - 40/5

= -5/-5

= -1

Determining the Probability value from Z-Table:

P(x<35) = 0.15866

Converting to percentage = 15.866%

We are asked how many will fail to meet this specification

We have 50,000 parts

Hence,

15.866% of 50,000 parts will fail to meet the specification

= 15.866% of 50,000

= 7933 parts

Therefore, 7933 parts will fail to meet the specifications.

b) How many would have a tensile strength in excess of 48 pounds?

z = (x-μ)/σ

x = 48 μ = 40 , σ = 5

z = 48 - 40/5

z = 8/5

z = 1.6

P-value from Z-Table:

P(x<48) = 0.9452

P(x>48) = 1 - P(x<48)

1 - 0.9452

= 0.054799

Converting to percentage

= 5.4799%

Therefore, 5.4799% will have an excess of (or will be greater than) 48 pounds

We are asked, how many would have a tensile strength in excess of 48 pounds?

This would be 5.4799% of 50,000 parts

= 5.4799% × 50,000

= 2739.95

Therefore, 2739.95 parts will have a tensile strength excess of 48 pounds

4 0
3 years ago
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