A) 8 - add up the how many numbers there are after the 4 on the left column
b) 41 - line up all of the numbers from least to greatest and find the middle number
c) 39 - do step b again but this time remove the oldest worker and add the younger one in
Answer:
Step-by-step explanation:
![\sf 3a^5-18a^3+6a^2\\\\HCF = 3a^2\\\\Take \ 3a^2 \ common\\\\= 3a^2(a^3-6a+2)\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%203a%5E5-18a%5E3%2B6a%5E2%5C%5C%5C%5CHCF%20%3D%203a%5E2%5C%5C%5C%5CTake%20%5C%203a%5E2%20%5C%20common%5C%5C%5C%5C%3D%203a%5E2%28a%5E3-6a%2B2%29%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
Step-by-step explanation:
Half life is the time taken by a radioactive substance to reduce of half of its original size
If the half life of radium is 1600, this means that the original radioactive substance N0 have reduced to N0/2 after 1600 years
if we are given N0 = 1000grams
The amount of the substance that will remain after 1600 years will be N0/2 i.e 1000/2 = 500g
<em>Hence 500 grams of radium will be left after 600years</em>
Simplify the ratio 8 to 2 to be 4 to 1
Now compare 4 to 1 and 10 to 1
4 is smaller than 10 so the ratio 8 to 2 is smaller.
-2-3x=3+1x
-2-3=1x+3x
-5=4x
x=-1.25
