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2 years ago

The minimum degree of rotation by which this octagon can map onto itself is?

2 answers:

8 0

Octogon has 8 vertices
to map onto itself, it goes to another vertex
assuming that it is a regular octogon
center=360
each vertex=360/8=45 degrees

therfor it moves 45 degrees to get to next verte which is same

45 degrees

Art [367]2 years ago

6 0

Answer:

The answer is 45 degrees.

Step-by-step explanation:

The minimum degree of rotation by which this octagon can map onto itself is 45 degrees.

A full rotation is 360°. One eighth of a rotation is $360/8=45$ degrees, and each one eighth of a rotation will map a regular octagon onto itself.

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Students in Mr. Clark's class are reading a book that has 180 pages.

Aleonysh [2.5K]

Answer:

Step-by-step explanation:

12 pages I think

4 0

2 years ago

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The graph shows the height of a hiker above sea level.

dimaraw [331]

The <u>correct answer</u> is:

B) The variables are height and time. For the first part of the graph, the height is increasing slowly, which means the hiker is walking up a gentle slope. Flat parts of the graph show where the elevation does not change, which means the trail is flat here. The steep part at the end of the graph shows that the hiker is descending a steep incline.

Explanation:

The variables are marked on the graph. Time is marked along the x-axis, which means it is the independent variable. Height is marked along the y-axis, which means it is the dependent variable.

The first part of the graph rises slowly. This means the elevation does not change much over the time; this would be consistent with a gentle slope being climbed.

The flat areas are where the elevation does not change. This would be consistent with the hiker resting.

The steep decrease at the end shows that the elevation goes down quickly. This is consistent with the hiker climbing down a steep slope.

3 0

3 years ago

Read 2 more answers

Evaluate <br> (-315) ×4<br> with the correct explaination

Naya [18.7K]

$\Large\textsf{\textbf{Answer\::}}$

-1, 260

$\large\textsf{\textbf{Calculations\;:}}$

First , take a look at the signs of the numbers we're asked to multiply .

One of them is negative , and the other one is positive .

If we have a negative number times a positive number , the product is a positive number .

Multiply :

(-315) × 4

-1, 260 (Ans)

$\footnotesize\text{hope\:helpful~}$

3 0

1 year ago

Find the linear approximation of the function f(x, y, z) = x2 + y2 + z2 at (4, 4, 7) and use it to approximate the number 4.022

miss Akunina [59]

Answer:

80.66

Step-by-step explanation:

$L\left( x \right) = f\left( a \right) + f'\left( a \right)\left( {x - a} \right)$

$f(x, y, z) = x^2+y^2+z^2$

Since we have three variables,

$L(x, y,z) = f(a, b,c) + f_x (a, b,c) (x - a) + f_y (a, b,c) (y - b) +f_z(a,b,c)(z-c)$

$f(4, 4, 7) = 4^2+4^2+7^2=81$

$f_x (a, b,c)=2x=2*4=8\\f_y (a, b,c)=2y=2*4=8\\ f_z(a,b,c)=2z=2*7=14$

Therefore:

$L(x, y,z) = 81+ 8(x - 4) + 8 (y - 4) +14(z-7)$

Using the above:

f(4.02, 3.99, 6.97) =81+ 8(4.02 - 4) + 8 (3.99 - 4) +14(6.97-7)=80.66.

The approximation of $4.02^2 + 3.99^2 + 6.97^2$ is 80.66000.

3 0

3 years ago

Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12

tiny-mole [99]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})$

$\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12$

5 0

2 years ago