All categories

2 years ago

The minimum degree of rotation by which this octagon can map onto itself is?

2 answers:

8 0

Octogon has 8 vertices
to map onto itself, it goes to another vertex
assuming that it is a regular octogon
center=360
each vertex=360/8=45 degrees

therfor it moves 45 degrees to get to next verte which is same

45 degrees

Art [367]2 years ago

6 0

Answer:

The answer is 45 degrees.

Step-by-step explanation:

The minimum degree of rotation by which this octagon can map onto itself is 45 degrees.

A full rotation is 360°. One eighth of a rotation is $360/8=45$ degrees, and each one eighth of a rotation will map a regular octagon onto itself.

You might be interested in

Area of rectangular figures

iren2701 [21]

Answer:

531 in^2

Step-by-step explanation:

21 x 18 = 378 in^2

17 x 9 = 153 in^2

378 + 153 = 531 in^2

3 0

2 years ago

Which of the following inequalities matches the graph?

Neko [114]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Which multiplication expression represents which multiplication expression represents 5^4

myrzilka [38]

Answer: 5x5x5x5

Step-by-step explanation:

5^4 is just multiplying 5 by itself 4 times

4 0

3 years ago

Solve for x.<br> 9(x + 2) = x - 6

jeyben [28]

Answer:

9(x + 2) = x - 6

9x+18=x-6

9x-x=-18-6

8x=-24

x=-24/8=-3 is your answer

4 0

3 years ago

Please help radical expression dividing

77julia77 [94]

$\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad 
\begin{cases}
63=3\cdot 3\cdot 7\\
6=2\cdot 3
\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}
\\\\\\
\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}$

$\bf \textit{now, rationalizing the denominator}\\\\
\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}
\\\\\\
\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}$

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.

6 0

2 years ago