How does energy move in ecosystems

2 answers:

5 0

Producers(plants) produce organic compounds through photosynthesis. They are then eaten by secondary consumers in the next tropic level who obtain the energy the plants have. Then those animals are eaten by more secondary consumers in the next trophic level, obtaining more energy, and the cycle continues

Harrizon [31]3 years ago

5 0

Organisms can be either producers or consumers in terms of energy flow through an ecosystem. Producers convert energy from the environment into carbon bonds, such as those found in the sugar glucose. ... A trophic level refers to the organisms position in the food chain. Autotrophs are at the base.

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Imagine you are an astronaut and you travel to a planet with a much larger mass than Earth. How would this affect your weight? E

Svetllana [295]

Answer:

Explanation:

It may not make any difference. The information missing is the radius of the planet.

However for the purposes of the question, let us assume that it is roughly the same diameter of the earth. Then the weight of anyone would increase if the mass is all that changes..

The formula governing your weight is F = G * m1 *m2 / r^2. If m1 is the mass of the planet and it increases a lot then m2 (you) should increase. The question is done by a proportion.

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2 years ago

What are some similarities between space and earth pollution?

yawa3891 [41]

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3 years ago

How many grams of sulfuric acid is needed to neutralize 380 ml of solution with pH = 8.94

erma4kov [3.2K]

Answer : The mass of sulfuric acid needed is $16.23\times 10^{-5}g$ .

Solution : Given,

pH = 8.94

Volume of solution = 380 ml = $380\times 10^{-3}$ $(1ml=10^{-3}L)$

Molar mass of sulfuric acid = 98.079 g/mole

As we know,

$pH+pOH=14\\pOH=14-8.94=5.06$

$pOH=-log[OH^-]$

$5.06=-log[OH^-]$

$[OH^-]=0.00000871=8.71\times 10^{-6}mole/L$

Now we have to calculate the moles of $OH^-$ .

Formula used : $Moles=Concentration\times Volume$

$\text{ Moles of }[OH^-]=\text{ Concentration of }[OH^-]\times Volume\\\text{ Moles of }[OH^-]=(8.71\times 10^{-6}mole/L)\times (380\times 10^{-3}L)=3309.8\times 10^{-9}moles$