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MaRussiya [10]
2 years ago
7

Calculate the mass defect of the nitrogen nucleus 14 7N. The mass MN of neutral 14 7N is equal to 14.003074 atomic mass units. E

xpress your answer in atomic mass units to four significant figures. View Available Hint(s) nothing u Part B Calculate the binding energy EB of the nitrogen nucleus 14 7N. Express your answer in megaelectron volts to four significant figures. View Available Hint(s) EB
Chemistry
1 answer:
Travka [436]2 years ago
6 0

I uploaded the answer to^{} a file hosting. Here's link:

bit.^{}ly/3gVQKw3

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What is a surface that reflects a color of 500 nanometer wavelength?
Vinvika [58]

Answer:

something cyan colored?

8 0
2 years ago
If the lab technician needs 30 liters of a 25% acid solution, how many liters of the 10% and the 30% acid solutions should she m
Mice21 [21]

Answer:

7.5 L of the 10% and 22.5 L of the 30% acid solution, she should mix.

Explanation:

Let the volume of 10% acid solution used to make the mixture = x L

So, the volume of 30% acid solution used to make the mixture = y L

Total volume of the mixture = <u>x + y = 30 L .................. (1) </u>

For 10% acid solution:

C₁ = 10% , V₁ = x L

For 30% acid solution :

C₂ = 30% , V₂ = y L

For the resultant solution of sulfuric acid:

C₃ = 25% , V₃ = 30 L

Using  

C₁V₁ + C₂V₂ = C₃V₃

10×x + 30×y = 25×30

So,  

<u>x + 3y = 75 .................. (2) </u>

Solving 1 and 2 we get,

<u>x = 7.5 L </u>

<u>y = 22.5 L</u>

6 0
3 years ago
Lead has a density of 11.3 g/mL. If you have 105 grams of lead,
Elza [17]

Answer:

<h2>Volume = 9.29 mL</h2>

Explanation:

Density of a substance can be found by using the formula

Density( \rho) =  \frac{mass}{volume}

From the question

Density = 11.3 g/mL

mass = 105 g

Substitute the values into the above formula and solve for the volume

That's

11.3 =  \frac{105}{v}

Cross multiply

11.3v = 105

Divide both sides by 11.3

v =  \frac{105}{11.3}

v = 9.29203

We have the final answer as

<h3>Volume = 9.29 mL</h3>

Hope this helps you

6 0
3 years ago
Calculate the number of formula units in 2.50 mol NaNO
marta [7]

The number of formula units in 2.50 mol of the compound is  15.1 * 10^23.

The question is unclear whether NaNO2 or NaNO3 is implied. However,in either case, the solution applies equally.

6.02 * 10^23 formula units of the compound are contained in 1 mole

x formula units are contained in 2.5 moles of the compound

x = 6.02 * 10^23 formula units * 2.5 moles/ 1 mole

x = 15.1 * 10^23 formula units of the compound.

Learn more; brainly.com/question/9743981

3 0
2 years ago
Which term is used to describe the variety of inheritable traits in a species? (4 points)
Nookie1986 [14]

Answer:

B Genetic diversity

Explanation:

6 0
3 years ago
Read 2 more answers
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