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notsponge [240]
3 years ago
10

2C2H2 + 5 O2 → 4CO2 + 2H2O

Chemistry
1 answer:
shtirl [24]3 years ago
6 0

Answer:

  • Option c. ΔH reaction = - 2,512.4 kJ

Explanation:

<u>1) Data:</u>

a) ΔHf C₂H₂ = 227.4 kJ

b) ΔHf CO₂ = -393.5 kJ

c) ΔHf H₂O = -241.8 kJ

<u>2) Chemical equation:</u>

  • 2C₂H₂ + 5 O2 → 4CO₂ + 2H₂O    [see the note below about the phases]

<u>3) Necessary assumptions:</u>

  • The phases of the reactants and products in the given reaction are the same at which the standard enthalpies of formation are given.

  • The reactant O₂ is at its fundamental state (gas) which implies that the correspondant standard enthaly of formation is zero.

  • The units of the given standard enthalpies are the same of the units indicated in the choices for the ΔH of the reaction (kJ).

<u>4) Formula:</u>

  • ΔH reaction = Δ∑ ΔH products - ∑ ΔH reactants

<u>5) Solution:</u>

  • ΔH reaction = 4×ΔHCO₂ + 2×ΔH₂O - 2×ΔH C₂H₂ - 5 ΔH O₂

  • ΔH reaction = 4×(-393.5 kJ) + 2×(-241.8 kJ) - 2×(227.4 kJ) - 5×0

  • ΔH reaction = - 2,512.4 kJ ← answer
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A certain water tower hold 4.6×10^5 gallons of water. find the volume of that water in liters.​
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The coefficients in the balanced chemical equation are used to determine mole ratios.
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Answer:

1 mole of HCl or NaOH gives you 1 mole of H2O , then the number of moles in H2O is: [ 1÷1×1 ] = 1 mole.

Explanation:

6 0
3 years ago
If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w
irinina [24]

Answer:

4.13 g

Explanation:

Data Given:

Amount of CO₂ Produced = 15 g

Amount of Oxygen = 11 g

Amount of Carbon used = ?

Solution:

Suppose Carbon dioxide (CO₂) is formed by the reaction of carbon and oxygen then the reaction will be as below

                            C   +   O₂    -------------> CO₂

                          1 mol    1 mol                  1 mol

we come to know from the above reaction that

1 mole of carbon react with 1 mole of oxygen to produce 1 mol of carbon dioxide.

molar mass of C = 12 g/mol

molar mass of O₂ = 32 g/mol

molar mass of CO₂ = 12 + 2(16) = 44 g/mol

if we represent mole in grams then

           C               +                        O₂                     ------------->        CO                 1 mol (12 g/mol)                      1 mol (32 g/mol)                      1 mol (44 g/mol)

                   

              C   +   O₂    -------------> CO₂

            12 g       32 g                   44 g

So,

we come to know that 32 g of Oxygen combine with 12 g  of oxygen produce 44 g CO₂

So now how much of Carbon will be combine with 11 g of oxygen

apply unity formula

                32 g of  O₂ ≅ 12 g of  C

                  11 g of O₂  ≅  g of  C

by doing cross multiplication

           g of C = 12 g x 11 g / 32 g

           g of C = 132 g / 32 g

           g of C = 4.13 g

So,

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

to check this answer

we use the above information

                     12 g of  C ≅ 44 g of CO₂

                     4.13 g of C ≅  g of  CO₂

by doing cross multiplication

                    g of  CO₂ = 44 g x 4.13 g / 12 g

                    g of CO₂ = 15g

So it is confirmed that

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

4 0
3 years ago
When 4.50 L of hydrogen gas react with an excess of nitrogen gas at standard temperature and pressure, how many liters of ammoni
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Answer:

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Solution:

The equation is as follow,

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According to equation,

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So,

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Solving for X,

                     X  =  (4.50 L × 44.8 L) ÷ 67.2 L

                     X  =  3.0 L of NH₃

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