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avanturin [10]
2 years ago
10

What is the name of this alkane? two central carbons are bonded to c h 3 at each end, h below, and c h3 above the left carbon an

d h above the right carbon. 1-methylbutane 2-methylbutane 1,2-triethylethane 1-dimethylpropane
Chemistry
1 answer:
Kazeer [188]2 years ago
4 0

The name of this alkane is with central carbons are bonded to c h 3 is 2-methylbutane.

<h3>What is alkane?</h3>

Alkanes belong to the family of  saturated hydrocarbons with carbon carbon single bond.

For the given alkane;

          CH₃    H

 CH₃ -  C   -  C - CH₃

            H      H

Thus, the name of this alkane is with central carbons are bonded to c h 3 is 2-methylbutane.

Learn more about alkane here: brainly.com/question/24270289

#SPJ4

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How many grams are in 5.00 moles of sodium carbonate?
dimulka [17.4K]

Answer:

= 529.9422

grams

Explanation:

5  moles Sodium Carbonate

= 529.9422

grams

8 0
3 years ago
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3 years ago
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A chemistry student weighs out 0.154 g of chloroacetic acid (HCH2CICO2) into a 250. mL volumetric flask and dilutes to the mark
erastovalidia [21]

Answer:

11.6 mL of 0.1400 M of NaOH is required to reach equivalence point.

Explanation:

Chloroacetic acid is an monoprotic acid.

Neutralization reaction: ClCH_{2}COOH+NaOH\rightleftharpoons ClCH_{2}COONa+H_{2}O

So, 1 mol of chloroacetic acid is neutralized by 1 mol of NaOH.

Molar mass of chloroacetic acid = 94.5 g/mol

So, 0.154 g of chloroacetic acid = \frac{0.154}{94.5} moles of chloroacetic acid

                                                     = 0.00163 moles of chloroacetic acid

Lets assume V mL of 0.1400 M of NaOH is required to reach equivalence point.

So, number of moles of NaOH needed to reach equivalence point

      = \frac{0.1400\times V}{1000} moles

So, \frac{0.1400\times V}{1000}=0.00163

or, V = 11.6

Hence, 11.6 mL of 0.1400 M of NaOH is required to reach equivalence point.

7 0
3 years ago
In the reaction of aluminum hydroxide and caldium nitrate, how many grams of calcium hydroxide will be formed if 12.55 g of alum
Dahasolnce [82]

Answer:

17.76g

Explanation:

We need to write a balanced chemical equation for the reaction:

2Al(OH)3 + 3Ca(NO3)2 ——> 3Ca(OH)2 + 2Al(NO3)3

In the reaction above, it can be seen that 2 moles of aluminum hydroxide yielded 3 moles of calcium hydroxide. This is the theoretical viewpoint.

Now we need to know what actually happened. We need to calculate the actual number of moles of aluminum hydroxide reacted l. We can get this by dividing the mass by the molar mass.

The molar mass of aluminum hydroxide is 27+ 3( 16+1)

= 27 + 51 = 78g/mol

The number of moles is thus: 12.55/78 = 0.16 moles

Now if 2 moles of aluminum hydroxide gave 3 moles of calcium hydroxide, 0.16moles will give : (0.16*3)/2 = 0.24moles

Now we can calculate the mass of calcium hydroxide formed. The mass of calcium hydroxide formed is the number of moles multiplied by the molar mass.

The molar mass of calcium hydroxide is; 40 + 2(17) = 74g/mol

The mass is thus =74 * 0.24 = 17.76g

7 0
3 years ago
You would expect magnesium to be most similar in properties to
gladu [14]

Answer:

Calcium

Explanation:

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3 0
3 years ago
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