Question

In ΔQRS, the measure of ∠S=90°, the measure of ∠R=29°, and SQ = 5.8 feet. Find the length of RS to the nearest tenth of a foot.

Answer 1

Answer:

10.5 ft

Step-by-step explanation:

In ΔQRS,

• m∠S=90°
• m∠R=29°,
• SQ = 5.8 feet.

See the diagram below.

The triangle is a Right Triangle,

Using trigonometric ratios,

$Tan R=\dfrac{|SQ|}{|RS|} \\Tan 29^\circ=\dfrac{5.8}{|RS|}\\ Cross multiply \\|RS|XTan 29^\circ=5.8\\|RS|=\dfrac{5.8}{Tan 29^\circ}\\ =10.5 ft (to the nearest tenth of a foot)$