Answer with Step-by-step explanation:
We are given that

We have to find T,N and B at the given point t > (1,
,1)



Now, substitute t=1













Answer:
40
Step-by-step explanation:
8 incorrect answers x -3 points per wrong answer. 64 - 24 points taken off = score of 40.
Answer:
54 students
Step-by-step explanation:
42 / 7 = 6
9 x 6 = 54
42 : 54 = 7 : 9
<span>1. Find the magnitude and direction angle of the vector.
2. Find the component form of the vector given its magnitude and the angle it makes with the positive x-axis.
<span>3. Find the component form of the sum of two vectors with the given direction angles.</span></span>