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3 years ago

7

Your job pays $8 an hour. Write a variable expression for your pay in dollars for working h hours

1 answer:

puteri [66]3 years ago

7 0

Lets say p is for pay. An expression for you would be p=8h because you would get 8 dollars per hour that you work. Then you would replace h with however many hours you worked. Ex: p=8h. You worked 12 hours, so 8 x 12 would equal 96, so you would get 96 dollars as your total pay, or p.

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The price of a watch was increased by 7% to £1350. What was the price before the increase? Give your answer to the nearest penny

frutty [35]

Answer:

1261.68

Step-by-step explanation:

1350 = the increased watch price= 107% of the original

1350= 1.07x

1261.68224299

Check:

7% of 1261.68224299 is 88.317757

1261.68224299 + 88.317757 = 1349.9 = 1350

Round:

1261.68224299

To the penny= to the hundreth= 1261.68

3 0

3 years ago

What is the value of y in the equation 2 + y = −3?

SOVA2 [1]

I believe that y is equal to -5.

y=-5

7 0

2 years ago

MARKING BRAILIEST!!!! Select the statement that describes this expression: 13 + fraction 1 over 2 x (6 ÷ 2 + 6)

Sauron [17]

Answer: D

You get the same answer from doing both!

3 0

3 years ago

Read 2 more answers

What is the ratio of quarters to nickels in a dollar

sleet_krkn [62]

For quarters we have:

$0.25x = 1$

Where,

x: number of quarters

Clearing x we have:

$x = \frac{1}{0.25}\\x = 4$

For nickels we have:

$0.05y = 1$

Where,

y: number of nickels

Clearing y we have:

$y = \frac{1}{0.05}\\y = 20$

Then, the ratio of quarters to nickels is:

$\frac{x}{y}= \frac{4}{20}$

Simplifying we have:

$\frac{x}{y} = \frac{1}{5}$

Answer:

The ratio of quarters to nickels in a dollar is:

$\frac{x}{y}= \frac{1}{5}$

5 0

3 years ago

Read 2 more answers

Is (1, 3) a solution to the system of equations listed below? (1 point) y= 6x -3 y = x - 2

ololo11 [35]

Answer:

The solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

Step-by-step explanation:

we can solve the system of equations to find the value of x and y and then verify if (1,3) is a solution or not.

The system of equation given is:

$y=6x-3\\y=x-2$

Solving:

Let:

$y=6x-3--eq(1)\\y=x-2--eq(2)$

Put value of y from equation 2 into equation 1

$y=6x-3\\Put\:y=x-2\\x-2=6x-3\\x-6x=-3+2\\-5x=-1\\x=\frac{-1}{-5}\\x=\frac{1}{5}$

Now, put value of x in equation 2 to find value of y

$y=x-2\\Put\:x=\frac{1}{5} \\y=\frac{1}{5} -2\\y=\frac{1-2*5}{5} \\y=\frac{1-10}{5}\\ y=\frac{-9}{5}$

So, the solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

7 0

3 years ago