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xenn [34]
3 years ago
14

Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. y = 64x−8x^2,

y = 0; about the y-axis.
Mathematics
1 answer:
Mandarinka [93]3 years ago
4 0
We need to get the limits first. When y = 0
0 = 64x - 8x^2
x = 0 and x = 8
The volume is
V = ∫ y dx from 0 to 8
V = ∫ (64x - 8x^2) dx from 0 to 8
V = 32x^2 - 8x^3/3 from 0 to 8
V = 682.67<span />
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The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as
bija089 [108]

Answer:

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(score of the 36 golfers was between 70 and 71)

\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}

P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%

P(70 \leq x \leq 71) = 47.7\%

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

8 0
4 years ago
OMG i'm freaking out. I take 8th grade algebra and my parents don't understand this. I need help! Can someone explain these two
Ivan
Sure, can I see the problem?
6 0
3 years ago
I need help. 10 POINTS!!
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5 0
4 years ago
The students in one social studies class were asked how many brothers and sisters (siblings) they each have. The dot plot here s
tester [92]

Answer:

1

Step-by-step explanation:

this is because if you look at the scatter plot count up the amount over 6 there is 1 dot meaning 1 student

3 0
3 years ago
Read 2 more answers
Explain me PLEASEEEE!!!
kirza4 [7]

Answer:

\frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}=a^{-7}=\frac{1}{a^{7}}

Step-by-step explanation:

Let us revise the properties of exponents

  • a^{m}.a^{n}=a^{m+n}
  • \frac{a^{m}}{a^{n}}=a^{m-n}
  • (a^{m})^{n}=a^{m.n}
  • a^{-m}=\frac{1}{a^{m} }

Let us use these properties to solve the question

→ By using the 3rd property above

∵ (a^{2})^{3}=a^{2.3}=a^{6}

∴ \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10} }

→ By using the 1st property above

∵ a^{6}.a^{-3}=a^{6+-3}=a^{6-3}=a^{3}

∴  \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}

→ By using the 2nd property above

∵ \frac{a^{3}}{a^{10}}=a^{3-10}=a^{-7}

∴  \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}=a^{-7}

→ By using the 4th property above

∵ a^{-7}=\frac{1}{a^{7}}

∴  \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}=a^{-7}=\frac{1}{a^{7}}

8 0
3 years ago
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