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xenn [34]
3 years ago
14

Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. y = 64x−8x^2,

y = 0; about the y-axis.
Mathematics
1 answer:
Mandarinka [93]3 years ago
4 0
We need to get the limits first. When y = 0
0 = 64x - 8x^2
x = 0 and x = 8
The volume is
V = ∫ y dx from 0 to 8
V = ∫ (64x - 8x^2) dx from 0 to 8
V = 32x^2 - 8x^3/3 from 0 to 8
V = 682.67<span />
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The formula of pi rs represents the formula to find the lateral surface area of a right cone.
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What is the derivative of y=ln(ln(x))?
Marysya12 [62]
Y=ln(ln(x)) y'=(1/x)/Ln(x)=1/xln(x)
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Emily has the following grades in his math class: Homework grades: 80, 100, 90, Quiz grades: 84, 90, 72, Test grades: 64,
Bess [88]

Answer:

75

Step-by-step explanation:

Homework mean x 10%: (80+100+90)/3 x 0.1 = 90 x 0.1 = 9

Quiz mean x 25%: (84+90+72)/3 x 0.25 = 20.5

Test mean x 45%: (64+72)/2 x 0.45 = 30.6

Sum of means/percentage of grade: 9 + 20.5 + 30.6 = 60.1/.8 = 75.125

8 0
3 years ago
On the number line 0.2 would be located. Choose a answer to make a true statement.
Mariulka [41]
Um, there are no choices, so I'll just tell you were it'd be located

Since 0.2 isn't yet 1, but its value is more than 0, it would be located in the middle of 1 and 0. 
6 0
3 years ago
3. Which of the following quadratic equations has no solution? A) 0 = −2(x − 5)2 + 3 B) 0 = −2(x − 5)(x + 3) C) 0 = 2(x − 5)2 +
klemol [59]

Answer:

D) 0 = 2(x + 5)(x + 3)

Step-by-step explanation:

Which of the following quadratic equations has no solution?

We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.

A) 0 = −2(x − 5)2 + 3

0 = -2(x - 5) × 5

0 = (-2x + 10) × 5

0 = -10x + 50

10x = 50

x = 50/10

x = 5

Option A has a solution of 5

B) 0 = −2(x − 5)(x + 3)

Take each of the factors and equate them to zero

-2 = 0

= 0

x - 5 = 0

x = 5

x + 3 = 0

x = -3

Option B has a solution by one of its factors as a positive value of 5

C) 0 = 2(x − 5)2 + 3

0 = 2(x - 5) × 5

0 = (2x -10) × 5

0 = 10x -50

-10x = -50

x = -50/-10

x = 5

Option C has a solution of 5

D) 0 = 2(x + 5)(x + 3)

Take each of the factors and equate to zero

0 = 2

= 0

x + 5 = 0

x = -5

x + 3 = 0

x = -3

For option D, all the values of x are 0, or negative values of -5 and -3.

Therefore the Quadratic Equation for option D has no solution.

3 0
3 years ago
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