Answer:
In terms of probablity (A - appetizer oredered, B - desert ordered)
P(A)=63%
P(B)=40%
P(AorB)=76%.
Using the formula:
P(AorB)=P(A)+P(B)-P(A&B) we get P(A&B)=63%+40%-76%=27% (probability we were looking for).
Answer: it is b
Step-by-step explanation:
I think I might be right I hope I am if not I’m so sorry
Answer:
the probability that no customer will arrive in the next 6 minutes = 0.36788 = 0.368
Step-by-step explanation:
If there are 10 customers per hour, this translates to 1 customer per 6 minutes
So, if there's a mean of 1 customer per 6 minutes, to obtain the probability that no customer will come in a 6 minute interval, this becomes a Poisson distribution problem.
The Poisson distribution formula is given by
P(X = x) = (e^-λ)(λˣ)/x!
where λ = mean = 1 customer per 6 minutes
x = 0 customer per 6 minutes
P(X=0) = (e⁻¹)(1⁰)/0! = 0.36788 = 0.368
Answer: See explanation
Step-by-step explanation:
3 × 10⁸ ÷ 3.4 × 10²
(3 × 100000000) ÷ (3.4 × 100)
300000000 ÷ 340
882352.94117
Round to the nearest hundredth
882352.94117 ≈ 882352.94
Round to the nearest tenth
882352.94117 ≈ 882352.9
Round to the nearest whole number
882352.94117 ≈ 882353
Hope I helped!
