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2 years ago

14

Do number 2 please. Please bots don’t answer! I just trying to get help :(

1 answer:

zavuch27 [327]2 years ago

8 0

Answer:

no 2. cube a' will be smaller because it was multiplied by a fraction

no 3. c

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How does the volume of a cone change if its radius and height are both tripled

Evgesh-ka [11]

The volume formula could be re-written to help understand this, as V = π*3r^2*3h. If you solve for this, you can conclude that the volume would be multiplied by 27.

6 0

3 years ago

What ratios are equivalent<br> to 3/5

barxatty [35]

The given ratios 3: 5 and 15: 25 are equal. Because when you divide the ratio 15: 25 by 5 on both numerator and denominator, the first ratio 3: 5 can be obtained. Similarly, when you multiply the first ratio 3: 5 by 5, the ratio 15: 25 can be obtained.

5 0

3 years ago

DedPeter [7]

Answer:

?=19

x=30

Step-by-step explanation:

5/6x - 1/5x = 19

5(5/6x) - 6(1/5x) = 19

25/30x-6/30x=19

19/30x=19

19x=19(30)

19x=570

x= 570/19

x=30

6 0

2 years ago

PLS HELP THIS IS HARD ANYONE PLS

Valentin [98]

This question is very oddly worded. The domain is the set of x-values, but this is a set of (x,y) ordered pairs.

I'm reading this question as "Here's a function, { (1,5), (2,1), (-1,-7) }. If this is reflected over the x-axis, what's the range?"

Assuming that is the question that is meant to be asked, reflecting a function over the x-axis will just change the signs of the y-values.

(1,5) -> (1,–5)

(2,1) -> (2,–1)

(-1,-7) -> (-1,+7)

I'd pick the third option.

6 0

3 years ago

baherus [9]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = $\frac{\sqrt3}{2}$

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

$\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}$

Proof LHS → RHS:

LHS cos 165

Double-Angle: cos (2 · 165) = 2 cos² 165 - 1

⇒ cos 330 = 2 cos² 165 - 1

⇒ 2 cos² 165 = cos 330 + 1

Given: $2 \cos^2 165 = \dfrac{\sqrt3}{2} + 1$

$\rightarrow 2 \cos^2 165 = \dfrac{\sqrt3}{2} + \dfrac{2}{2}$

Divide by 2: $\cos^2 165 = \dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \dfrac{2\sqrt3+4}{8}$

Square root: $\sqrt{\cos^2 165} = \sqrt{\dfrac{4+2\sqrt3}{8}}$

Scratchwork: $\cos^2 165 = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2$

$\rightarrow \cos 165 = \pm \dfrac{\sqrt3+1}{2\sqrt2}$

Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

$\rightarrow \cos 165 = - \dfrac{\sqrt3+1}{2\sqrt2}$

LHS = RHS $\checkmark$

4 0

3 years ago