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3 years ago

What is the perimeter of 16cm 25cm

Mathematics

2 answers:

Cloud [144]3 years ago

4 0

Im guessing this is a rectangle? If so it would be
16+16+25+25
32+50
82 is the perimeter

Sergeu [11.5K]3 years ago

4 0

16 + 16 = 32 + 25 = 57 + 25 = 82. 82 is the perimeter.

Brainliest please? :)

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Find the length of side x in simplest radical form with a rational denominator

svetlana [45]

Answer:

Step-by-step explanation:

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3 years ago

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business school graduates showed that 75 had gone to graduate school while in a random sample of 500 non-business graduates, 137

Lana71 [14]

Answer:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the upper limit would be -0.0318

Step-by-step explanation:

Assuming this complete question :A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates who go on to graduate school within five years after graduation and the proportion of non-business school graduates who attend graduate school. A random sample of 400 business school graduates showed that 75 had gone to graduate school while in a random sample of 500 non-business graduates, 137 had gone on to graduate school. Based on a 95 percent confidence level, what is the upper limit of the confidence interval estimate?

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion for graduate school

$\hat p_A =\frac{75}{400}=0.1875$ represent the estimated proportion for graduate school

$n_A=400$ is the sample size required for graduate school

$p_B$ represent the real population proportion for non graduate school

$\hat p_B =\frac{137}{500}=0.274$ represent the estimated proportion for non graduate school

$n_B=500$ is the sample size required for non graduate school

$z$ represent the critical value for the margin of error

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the upper limit would be -0.0318

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3 years ago

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Can someone be helpful

Murrr4er [49]

I would be happy to be helpful!

5 more than the sum of -1 and -12

lets start with the 2nd part, the sum of -1 and -12

sum means adding 2 things together, so -1 + -12 = <u>-13</u>

now lets work on the first part again, it said 5 MORE, more means add as well, so

-13 + 5 = -8

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