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11111nata11111 [884]
4 years ago
8

Here is the histogram of a data distribution. All class widths are 1. What is the median of this distribution?

Mathematics
1 answer:
Bingel [31]4 years ago
6 0

Answer:

The median is 4.

Step-by-step explanation

if you layout all the number, you get

1,2,2,3,3,3,4,5,5,5,6,6,7

So, to find the median you find the number(s) right in the middle.

(Ex. 3,4,5; 4 is the median)

(Ex. 3,4,5,7; 4.5 is the answer)

The middle number of

1,2,2,3,3,3,4,5,5,5,6,6,7

is 4, so 4 is the median.

hope this helps. :)

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Describe and correct the error in finding the tenth term of the arithmetic sequence 4, 12, 20, 28.
ycow [4]

Answer: The tenth term is 76

=======================================================

Explanation:

We use this arithmetic sequence formula to get the nth term

a_n = a_1 + d(n-1)

Plug in a_1 = 4, \ d = 8, \ n = 10 and you should get the following:

a_n = a_1 + d(n-1)\\\\a_{10} = 4 + 8(10-1)\\\\a_{10} = 4 + 8(9)\\\\a_{10} = \textbf{76}\\\\

The tenth term is <u>76</u>

---------

We can verify this by listing out the terms one by one. Start at 4, add on 8 each time, until you generate the 10th term. A table like the one shown below is a good way to keep track of all the terms.

\begin{array}{c|c}\boldsymbol{n} & \boldsymbol{a_n}\\1 & 4\\2 & 12\\3 & 20\\4 & 28\\5 & 36\\6 & 44\\7 & 52\\8 & 60\\9 & 68\\10 & \textbf{76}\\\end{array}

---------

In short, the error is with the "10" in the expression 4+10(8). The student should have used 9 instead. This is because of the n-1 term in a_n = a_1 + d(n-1) which shifts everything one spot to the left.

7 0
2 years ago
The cards below have a mean of 25. What is the missing number?: ? 19, 22, 31
GuDViN [60]

Answer: Its 28.

Step-by-step explanation:

4 0
3 years ago
The volume of ice-cream in the cone is half the volume of the cone. The cone has a 3 cm radius and
zhannawk [14.2K]

Answer:

h = 5 cm

Step-by-step explanation:

Given that,

The volume of ice-cream in the cone is half the volume of the cone.

Volume of cone is given by :

V_c=\dfrac{1}{3}\pi r^2h

r is radius of cone, r = 3 cm

h is height of cone, h = 6 cm

So,

V_c=\dfrac{1}{3}\pi (3)^2\times 6\\\\V_c=18\pi\ cm^3

Let V_i is the volume of icecream in the cone. So,

V_i=\dfrac{18\pi}{2}=9\pi\ cm^3

Let H be the depth of the icecream.

Two triangles formed by the cone and the icecream will be similiar. SO,

\dfrac{H}{6}=\dfrac{r}{3}\\\\r=\dfrac{H}{2}

So, volume of icecream in the cone is :

V_c=\dfrac{1}{3}\pi (\dfrac{h}{2})^2(\dfrac{h}{3})\\\\9\pi=\dfrac{h^3}{12}\pi\\\\h^3=108\\\\h=4.76\ cm

or

h = 5 cm

So, the depth of the ice-cream is 5 cm.

8 0
4 years ago
72 games 20% discount
Firdavs [7]
72*.2=14.4

72-14.4= 57.6

Games cost $57.60
3 0
3 years ago
Read 2 more answers
Find x and y. please I need help its so confusing
IrinaVladis [17]
Sin 30=opposite side/hypotenuse =8/x
1/2=8/x so 1•x=2•8; x=16

Sin60= opposite side/hypotenuse=y/16
(Sqrt 3)/2=y/16 so 2•y=16• sqrt 3; y=13.856
5 0
4 years ago
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