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3 years ago

How do you calculate viewing area

Mathematics

1 answer:

Sauron [17]3 years ago

8 0

Answer:

The way to calculate viewing area would be base multiplied by height, but if you would be more specific I would provide a more in detail answer.

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Question

marin [14]

Answer:

Step-by-step explanation:

From the table attached,

x-intercept of the linear function is, the value of 'x' when f(x) = 0

x = 3 [x-intercept]

Function 'g' is the sum of 2 and the cube root of the sum of three time x and 1.

g(x) = $2+\sqrt[3]{3x+1}$

For x-intercept,

g(x) = 0

$2+\sqrt[3]{3x+1}=0$

3x + 1 = (-2)³

3x + 1 = -8

3x = -8 - 1

3x = -9

x = -3

Therefore, the x-intercept of function 'f' is different or greater than the x-intercept of function g.

4 0

3 years ago

Is this figure a polygon? Explain.

denis-greek [22]

Yes.

It’s a flat figure (2D), and all of its lines are connected with one another. There aren’t any open points/lines. It’s closed to create a shape. This means it’s a polygon.

3 0

2 years ago

Look at the picture

Sonbull [250]

$\large\displaystyle\text{$\begin{gathered}\sf 9|x-8| < 36 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf Divide \ both \ sides \ by \ 9. \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \frac{9(|x-8|)}{9} < \frac{36}{9} \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf Solve \ Absolute \ Value. \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf We \ know \ x-8 < 4 \ and \ x-8 > -4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf x-8 < 4 \ (Condition \ 1) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 < 4+8 \ (Add \ 8 \ to \ both \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x < 12 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf x-8 > -4 \ (Condition \ 2) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 > -4+8 \ (Add \ 8 \ to \ both \ \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x > 4 \end{gathered}$}$

$\underline{\boldsymbol{\sf{Answer}}}$

$\boxed{\large\displaystyle\text{$\begin{gathered}\sf x < 12 \ and \ x > 4 \end{gathered}$} }$

$\large\displaystyle\text{$\begin{gathered}\sf Therefore,\bf{\underline{the \ correct \ option}} \ \end{gathered}$}\large\displaystyle\text{$\begin{gathered}\sf is \ \bf{\underline{"A"}}. \end{gathered}$}$

6 0

2 years ago

If you wanted to make the graph of y=3x+1 steeper, which equation could to use?

Sidana [21]

Answer:

Literally use any answer which has a higher slope so . . .

y = 10x + 1

y = 1000000000000000000x + 1

and so on.

7 0

3 years ago

Find the common difference of the arithmetic sequence –9,–13, -17,...

Semenov [28]

Answer:

-4

Step-by-step explanation:

t2 - t1

-13 - (-9)

-13 + 9

= -4

6 0

3 years ago