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3 years ago

What happens to the value of the expression 80/h as h increases

Mathematics

1 answer:

snow_lady [41]3 years ago

5 0

As h increases 80/h decreases . When h approaches infinity 80/h approaches zero.

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Please help me with 1-5

kari74 [83]

Answer:

1. 79.2 inches

2. 114

3. 55.2

4. 2599.992

5. 2350

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Television networks frequently run public opinion polls on issues of concern. One network conducted a scientific poll asking a q

kobusy [5.1K]

Answer:

Option d

Step-by-step explanation:

Given that television networks frequently run public opinion polls on issues of concern. One network conducted a scientific poll asking a question concerning the approval rating of the way President Obama was handling the Iraq War. At about the same time a second network ran an online poll using a very similar question.

Observed data is

Poll Scien Online total

approve 339 385 724

disapprove 780 573 1363

1119 958 2087

$H_0: Both scientific and online are consistent\\H_a: not consistent$

(Two tailed chi square test)

Let us find out expected and chi square

Expected = row total x column total/grand total

The cell count expected in the online poll for those who approve

= $\frac{724*968}{2087} \\=333.94$

chi square = 7.81

Hence option d is right.

4 0

3 years ago

Let X1, . . . ,Xn be an i.i.d. random sample from a N(0, 1) population. Define Y1 = 1 n n X i=1 Xi , Y2 = 1 n n X i=1 |Xi| . Cal

nalin [4]

For each $1\le i\le n$ , $E[X_i]=0$ , so that

$\displaystyle E[Y_1]=E\left[\frac1n\sum_{i=1}^nX_i\right]=\frac1n\sum_{i=1}^nE[X_i]=0$

Meanwhile,

$\displaystyle E[Y_2]=\frac1n\sum_{i=1}^nE[|X_i|]$

Each of the $X_i$ have PDF

$f_{X_i}(x)=\dfrac1{\sqrt{2\pi}}e^{-x^2/2}$

for $x\in\Bbb R$ . From this we get

$E[|X_i|]=\displaystyle\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty|x|e^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}\int_0^\infty xe^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}$