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Monica [59]
3 years ago
15

(2m² + 6m) + (m² – 5m +7) а. Зm² + m b. Зm² - m +7 с. m² + 11m - 7 d. 3m² + m +7​

Mathematics
2 answers:
grigory [225]3 years ago
4 0
The answer is D. 3m^2 + m + 7 !!
pychu [463]3 years ago
4 0

Answer:

3m² + m + 7​

Explanation:

(2m² + 6m) + (m² – 5m + 7)

Remove Parenthesis

2m² + 6m + m² – 5m + 7

Group Like Terms

2m² + m² + 6m - 5m + 7

Add Similar Elements

2m² + m²: 3m²

6m - 5m = m

3m² + m + 7

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Step-by-step explanation:

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3 years ago
Please help!!!!!!!!!!!!
blagie [28]
Point-slope form is y - y1 = m (x + x1)

First you need to find m [slope] by subtract y2 and y1 and divide it by the outcome of x2 - x1

13 - (-9) = 22
-2 - 9 = -11
22/-11 = -2

Plug in the first point (as instructed) into the equation.

y - (-9) = -2 (x - 9)

Simplify the beginning.

y + [9] = [-2] (x + [-9])

(The brackets are the fill in the blanks)


7 0
3 years ago
The critical points of a rational inequality are -1,3, and 4. Which set of points can be tested to find a complete solution to t
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3 0
3 years ago
Give a rule of the piecewise-defined function.
nataly862011 [7]

The equation of the piecewise function is f(x) = \left[\begin{array}{ccc}3&x \le -1\\-1&x > 2\end{array}\right

<h3>The piecewise function</h3>

On the graph, we have:

  • y = 3 for all x values not more than -1
  • y = -1 for all values greater than 2

Hence, the piecewise function is:

f(x) = \left[\begin{array}{ccc}3&x \le -1\\-1&x > 2\end{array}\right

<h3>The domain of the function</h3>

This is the set of input values

In (a), we have:

x ≤ -1 and x > 2

Hence, the domain is (∞, 3] u (2, ∞)

<h3>The range of the function</h3>

This is the set of output values

In (a), we have:

f(x) = 3 and f(x) -1

Hence, the range is [3] u (-1)

Read more about piecewise function at:

brainly.com/question/18859540

#SPJ1

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1 year ago
Help please and thank you (is also my bday haha)
Marysya12 [62]

Answer:

the center point of the cross in the middle

Step-by-step explanation:

I forgot how to explain it, but im 99.99% sure thats the right answer. also, happy birthday

5 0
3 years ago
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