The solution would be like this for this specific problem:
sin(θ°) = √(2)/2
θ° = 360°n + sin⁻¹(√(2)/2) and θ° = 360°n + 180° −
sin⁻¹(√(2)/2)
θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ
360°*0 + 45° = 45°
360°*0 + 135° = 135°
360°*1 + 45° = 405°
<span>sin(225°) = -√(2)/2
</span>225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta
cannot be 225 degrees.
Answer: y= -1/2x + 5/2
Step-by-step explanation:
3x = 15 -6y
+6y + 6y
3x +6y =15
-3x -3x
6y= 15-3x divide both sides by 6
y= 15/6 - 3/6x
in slope intercept form us y= -3/6x + 15/6 in simplest form is y= -1/2x + 5/2
Answer:
They can either decrease the confidence level or increase the sample size, that is, survey more students.
Step-by-step explanation:
The width of a confidence interval is given by:

In which z is the critical value correponding to the confidence level(higher confidence level, higher z is),
is the standard deviation of the population and n is the size of the sample.
The students realize that this interval contains a large margin of error. What can they do to make a narrower interval?
Looking at the formula for M, they can either decrease the confidence level or increase the sample size, that is, survey more students.
Answer:y = k x + 1
(1,3)
3 = k(1) + 1
2 = 1k
k = 2
Step-by-step explanation: