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r-ruslan [8.4K]
3 years ago
15

Which is the most accurate description of the polygon?

Mathematics
2 answers:
Sholpan [36]3 years ago
6 0
Hey there,

Your question states: <span>Which is the most accurate description of the polygon?
Based on this picture above, this looks like a rhombus. Your correct answer would be </span>\boxed{A}
<span>
Hope this helps.
~Jurgen


</span><span>
</span>

Digiron [165]3 years ago
5 0
I would say that It is a rhombus.So it is A.
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The price of the new stock would $5.25 because you have to add the $4.75 and $0.50 to find the new price
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3 years ago
A water tank is being filled by pumps at a constant rate. The volume of water in the tank V, in gallons, is given by the equatio
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Answer:

65 gallons per minute

Step-by-step explanation:

The total volume of the tank at any given time is given by the equation:

V(t) = 65t + 280

In order to find the rate of change of volume, we can simply differentiate this equation with respect to time. This will give us the rate of change of the volume or the rate at which water is being pumped into the tank.

Differentiating the above equation we get:

V'(t) = 65

So we can see that the rate at which water is being pumped into the tank is 65 gallons per minute

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3 years ago
Michel is headed to his aunt's house. For the first 2 hours he drives at 55 mph. For the next hour, he drives 70 mph. For the fi
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Step-by-step explanation:


5 0
2 years ago
Read 2 more answers
If a = 3 and b = 2, what is the value of the expression 11 + a - b ?
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Hope this helps!
4 0
3 years ago
A train slows down as it rounds a sharp horizontal turn, going from 92.0 km/h to 54.0 km/h in the 16.0 s that it takes to round
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Calculation of centripetal acceleration(ac):

a_c=\frac{v^2}{r}

we can change our speed in terms of m/s

v=54km/h=54*\frac{1000}{3600} m/s

now, we can plug these values

a_c=\frac{(54*\frac{1000}{3600})^2}{130}

a_c=1.73077m/s^2

Calculation of tangential acceleration(at):

a_t=\frac{\Delta v}{\Delta t}

now, we can plug values

a_t=\frac{(54-92)*\frac{1000}{3600} }{16}

now, we can simplify it

a_t=-0.65972 m/s^2

Calculation of resultant acceleration:

a=\sqrt{(a_c)^2+(a_t)^2}

now, we can plug values

a=\sqrt{(1.73077)^2+(-0.65972)^2}

a=1.85224m/s^2.............Answer

4 0
3 years ago
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