Answer:
Piano fits in the given space.
Step-by-step explanation:
Given: Length of Piano = ![\frac{19}{4}\,feet](https://tex.z-dn.net/?f=%5Cfrac%7B19%7D%7B4%7D%5C%2Cfeet)
Length of Space 5 foot
To find: If piano fits in the space or not
Piano fits in the space if its length is less than length of space .i.e., 5 foot
length of piano =
feet
feet is just plural of foot
So, conversion of unit not needed
Length of piano is improper fraction ( fraction whose numerator is gretaer than denominator ) So, it ca be expressed in mixed fraction.
This shows that Piano's length is more than 4 but less than 5.
Therefore, Piano fits in the given space.