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crimeas [40]
3 years ago
10

1) Function B: x -> /5 -> +1 = y

Mathematics
1 answer:
GalinKa [24]3 years ago
7 0

Answer:

Suppose f and g are two functions such that

1. (g ◦ f)(x) = x for all x in the domain of f and

2. (f ◦ g)(x) = x for all x in the domain of g

then f and g are said to be inverses of each other. The functions f and g are said to be

invertible.

. Properties of Inverse Functions: Suppose f and g are inverse functions.

• The rangea of f is the domain of g and the domain of f is the range of g

• f(a) = b if and only if g(b) = a

• (a, b) is on the graph of f if and only if (b, a) is on the graph of g

Step-by-step explanation:

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Graph A represents the exponential equation y=4(6) and graph B represents y=6(4). which statements are true about graph a and gr
PtichkaEL [24]

Answer:

Step-by-step explanation:The following statements are true about exponential functions:

-The domain is all real numbers.

- The input to an exponential function is the exponent.

- The base represents the multiplicative rate of change.

The reason why the other two options are wrong are explained below:

The range of exponential functions is not always includes negative numbers; on the contrary, the range is the set of all positive real numbers.

The graph of an exponential function does not have a horizontal asymptote at x = 0; contrarily, the equation of the horizontal asymptote of the graph of is y = 0, which is the x-axis.

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Good to know, I think?

6 0
3 years ago
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Given: △PRS, RS=10<br> m∠P=45°, m∠S=60°<br> Find: Perimeter of △PRS
Keith_Richards [23]

The law of sines can be used to find the missing side lengths.

... RP = sin(60°)/sin(45°)·10 = 10√(3/2) ≈ 12.247

... PS = sin(75°)/sin(45°)·10 ≈ 13.660

Then the perimeter is

... perimeter = RS + RP + PS

... = 10 + 12.247 + 13.660 ≈ 35.91 . . . .units

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4 years ago
5x+2y=-3;x+5y=4<br>plz answer me​
Alex17521 [72]

Answer:

x = -1 and y = 1

Step-by-step explanation:

5x + 2y = -3 . . . . . . . (i)

x + 5y = 4 . . . . . . . (ii)

  • Finding x in terms of y from eq. (ii) :-

x + 5y = 4

x = 4 - 5y

  • Placing this value of x in eq. (i) :-

5(4 - 5y) + 2y = -3

20 - 25y + 2y = -3

-23y = - 23

<u>y = 1</u>

  • Placing the value of y in eq. (i)

5x + 2(1) = -3

5x + 2 = -3

5x = - 5

<u>x = -1</u>

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3 years ago
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DENIUS [597]
This is number 7 and 9

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