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slavikrds [6]
3 years ago
5

Solve the equation 8d – 4d – 6d – 8 = 2d A. 0 B. -4 C. -2 D. -4

Mathematics
2 answers:
leonid [27]3 years ago
4 0
Hi there! The answer is C. - 2

8d - 4d - 6d - 8 = 2d
First we collect the terms.

- 2d - 8 = 2d
Next subtract 2d from both sides.

- 4d - 8 = 0
Add 8 to both sides.

- 4d = 8
Finally divide both sides by -4.

d = \frac{8}{ - 4} = - 2
Therefore, the answer is C. -2

~ Hope this helps you!
skad [1K]3 years ago
3 0
<span>8d – 4d – 6d – 8 = 2d

Combine common terms:
-2d - 8 = 2d

Add 2d to both sides:
-8 = 4d

Swtich sides:
4d = -8

Divide both sides by 4:
d = -2

Answer: - 2
</span>
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Answer:

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6 0
2 years ago
This year, a baseball player made 92 hits out of 564 times at bat. Another player made 84 hits out of 634 times at bat. Did the
Advocard [28]
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6 0
3 years ago
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cestrela7 [59]
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(x-h)^2 + (y-k)^2 =r^2
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7 0
3 years ago
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Use inductive reasoning to describe the pattern. Then find the next two numbers in the pattern. 1, 4, 7, 10, . . .
Kisachek [45]

Option a: add 3 to the previous term; 13, 16

Explanation:

The sequence is 1, 4, 7, 10, ....

We need to determine the next two terms of the sequence.

Hence to find the next two terms, first we shall find the common difference between every two terms.

Common difference between 1 and 4 = 4-1=3

Similarly, common difference between 4 and 7 = 7-4=3

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So, the next two terms will also have the same common difference 3.

To determine the next two terms, first we shall add 3 to the term 10, we get,

10+3=13

Similarly, adding 3 to the term 13, we get,

13+3=16

Thus, the sequence is 1, 4, 7, 10, 13, 16, .....

Thus, add 3 to the previous term; 13, 16

Hence, option a is the correct answer.

6 0
3 years ago
A parking lot is 100 yards long what is the length off 3/4if the parking lot
andriy [413]
I think you mean:
A parking lot is 100 yards long. What is the length of 3/4 of the parking lot?

3/4 * 100            Mathematical Expression.

3/1 * 25              Simplify.

75                       Multiply.

Final Answer: 75 yards long
4 0
3 years ago
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