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galben [10]
3 years ago
9

Solve for x: 1 over 3 (2x − 8) = 4.

Mathematics
2 answers:
Elena-2011 [213]3 years ago
7 0
The answer is c because since twenty minus eight is twelve one third times twelve is four
S_A_V [24]3 years ago
3 0
The correct answer is:  [C]:  "10" . 
____________________________________________________
    →  " x = 10 "  .
____________________________________________________
Explanation:
____________________________________________________
 Given:
____________________________________________________
    →   (1/3) * (2x − 8) = 4  ;  Solve for "x" ; 
____________________________________________________
To get rid of the "fraction" ; multiple BOTH SIDE of the equation by "3" : 

   →   3 * { (1/3) * (2x − 8) } = 3 * 4 ; 

to get: 

 1(2x − 8) = 12 ; 

↔  2x − 8 = 12 ; 

Add "8" to BOTH SIDES of the equation ; 

 →  2x − 8 + 8 = 12 + 8 ;

to get:

→  2x = 20 ; 

Divide EACH SIDE of the equation by "2" ; 
 to isolate "x" on one side of the equation; & to solve for "x" 

→ 2x / 2  = 20/ 2 ; 

→  x = 10  ;  which is:  Answer choice:  [C]:  "10" .
________________________________________________
Let us check our answer:  " x = 10" ;  by plugging in "10" for all values of "x" into the original equation; to see if the answer holds true for the equation ; that is, to see if both sides of the equation are equal when "x = 10" ; 

The original equation:  " (1/3) * (2x − 8) = 4 " .

    →  (1/3) * [2(10) − 8)  =?  4 ?? ;

    →  (1/3) * [20 − 8)  =?  4 ?? ; 

    →  (1/3) * (12)  =?  4 ?? ;   Yes!
_____________________________________________
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Answer:

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Step-by-step explanation:

1. Approach

In order to solve this problem, one will have to divide the figure up into simple shapes. A picture is attached showing how the shape is divided up for this answer. Find the area of each region, then add up the results to find the total area.

2. Area of Region 1

As one can see, the length of (Region 1), as given is (6), the width is (3). To find the area multiply the length by the width.

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3. Area of Region 2

In (Region 2), the length is given, (12). However, one must find the width, this would be the size of the total side, minus the width of (Region 1). Multiply the length by the side to find the area.

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4. Area of Region 3

In (Region 3), the length of the figure is (2), the width is (3). To find the area, multiply the length by the width.

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4) Find the Q1 and Q3. Q1 = median of the lower half of the data; Q3 = median of the higher half of the data. Q1 and Q3 have even sets so its median cannot be defined.
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We can then use the Alternative definition of IQR.
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5 0
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