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galben [10]
3 years ago
9

Solve for x: 1 over 3 (2x − 8) = 4.

Mathematics
2 answers:
Elena-2011 [213]3 years ago
7 0
The answer is c because since twenty minus eight is twelve one third times twelve is four
S_A_V [24]3 years ago
3 0
The correct answer is:  [C]:  "10" . 
____________________________________________________
    →  " x = 10 "  .
____________________________________________________
Explanation:
____________________________________________________
 Given:
____________________________________________________
    →   (1/3) * (2x − 8) = 4  ;  Solve for "x" ; 
____________________________________________________
To get rid of the "fraction" ; multiple BOTH SIDE of the equation by "3" : 

   →   3 * { (1/3) * (2x − 8) } = 3 * 4 ; 

to get: 

 1(2x − 8) = 12 ; 

↔  2x − 8 = 12 ; 

Add "8" to BOTH SIDES of the equation ; 

 →  2x − 8 + 8 = 12 + 8 ;

to get:

→  2x = 20 ; 

Divide EACH SIDE of the equation by "2" ; 
 to isolate "x" on one side of the equation; & to solve for "x" 

→ 2x / 2  = 20/ 2 ; 

→  x = 10  ;  which is:  Answer choice:  [C]:  "10" .
________________________________________________
Let us check our answer:  " x = 10" ;  by plugging in "10" for all values of "x" into the original equation; to see if the answer holds true for the equation ; that is, to see if both sides of the equation are equal when "x = 10" ; 

The original equation:  " (1/3) * (2x − 8) = 4 " .

    →  (1/3) * [2(10) − 8)  =?  4 ?? ;

    →  (1/3) * [20 − 8)  =?  4 ?? ; 

    →  (1/3) * (12)  =?  4 ?? ;   Yes!
_____________________________________________
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  1. h = -16t^2 + 73t + 5
  2. h = -16t^2 + 5
  3. h = -4.9t^2 + 73t + 1.5
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Step-by-step explanation:

The general equation we use for ballistic motion is ...

  h(t)=\frac{1}{2}gt^2+v_0t+h_0

where g is the acceleration due to gravity, v₀ is the initial upward velocity, and h₀ is the initial height.

The values of g commonly used are -32 ft/s², or -4.9 m/s². Units are consistent when the former is used with velocity in ft/s and height in feet. The latter is used when velocity is in m/s, and height is in meters.

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Dwayne throws a ball with an initial velocity of 73 feet/second. Dwayne holds the ball 5 feet off the ground before throwing it. (h = -16t^2 + 73t + 5)

A watermelon falls from a height of 5 feet to splatter on the ground below. (h = -16t^2 + 5)

Marcella shoots a foam dart at a target. She holds the dart gun 1.5 meters off the ground before firing. The dart leaves the gun traveling 73 meters/second. (h = -4.9t^2 + 73t + 1.5)

Greg drops a life raft off the side of a boat 1.5 meters above the water. (h = -4.9t^2 + 1.5)

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<em>Additional comment on these scenarios</em>

The dart and ball are described as being launched at 73 units per second. Generally, we expect launches of these kinds of objects to have a significant horizontal component. However, these equations are only for <em>vertical</em> motion, so we must assume the launches are <em>straight up</em> (or that the up-directed component of motion is 73 units/second).

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