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Umnica [9.8K]
3 years ago
7

What does “each point of a line maps to itself” mean? I don’t understand it what it means for it to map to itself.

Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0
Can u show me the graph or map your talkin about
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The graph of the function f(x) =4√x is shown.
mixer [17]

Answer:

the domain is equal to all real numbers greater than or equal to 0

Step-by-step explanation:

The domain is all the numbers in which the graph reaches in regards to the x axis

We can see from the graph that it starts at 0 and then moves right

THis means that the domain is equal to all real numbers greater than or equal to 0

6 0
3 years ago
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Find the missing angle
Natasha_Volkova [10]

Answer:

56deg

Step-by-step explanation:

A triangle has 180deg.

180 = 68 + 56 + x       >> add 68 and 56

180 = 124 + x              >> subtract 124 from both sides

56 = x

The missing side is 56deg

7 0
3 years ago
a 3 pound pork loin can be cut into 10 pork chops of equal weight. how many ounces are in each pork chop? please show your work
Artyom0805 [142]
Attached a solution and showed work.

3 0
4 years ago
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Order the fractions 1 / 6, 2 / 5, 3 / 5, 3 / 7 from least to greatest,
romanna [79]

Answer:

1/6, 3/7, 2/5, 3/5

Step-by-step explanation:

6 0
3 years ago
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This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
ANTONII [103]

Answer:

Maximum value: 3* \sqrt{n}

Minimum value: -3* \sqrt{n}

Step-by-step explanation:

Let g(x) = x_1^2 + x_2^2+x_3^2+ ----+ x_n^2 , the restriction function.The Lagrange Multiplier problem states that an extreme (x1, ..., xn) of f with the constraint g(x) = 9 has to follow the following rule:

\nabla{f}(x_1, ..., x_n) = \lambda \nabla{g} (x_1,...,x_n)

for a constant \lambda .

Note that the partial derivate of f respect to any variable is 1, and the partial derivate of g respect xi is 2xi, this means that

1 = \lambda 2 x_1

Thus,

x_i = \frac{1}{2\lambda} = c

Where c is a constant that doesnt depend on i. In other words, there exists c such that (x1, x2, ..., xn) = (c,c, ..., c). Now, since g(x1, ..., xn) = 9, we have that n * c² = 9, or

c = \, ^+_- \, \sqrt{\frac{9}{n} } = \, ^+_- \frac{3}{\sqrt{n}}

When c is positive, f reaches a maximum, which is \frac{3}{\sqrt{n}}  +  \frac{3}{\sqrt{n}} +  \frac{3}{\sqrt{n}}  + ..... +  \frac{3}{\sqrt{n}}  = n *  \frac{3}{\sqrt{n}}  = 3 * \sqrt{n}

On the other hand, when c is negative, f reaches a minimum, -3 * \sqrt{n}

8 0
4 years ago
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