Answer:
- 6 2/3 qt 80%
- 13 1/3 qt 20%
Step-by-step explanation:
It is often convenient to solve a mixture problem by letting a variable represent the quantity of the higher-concentration contributor to the mix.
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We can let x represent the number of quarts of 80% solution needed. Then (20-x) is the number of quarts of 20% solution needed. The amount of salt in the final mix is ...
0.80x +0.20(20-x) = 0.40(20)
0.60x = 0.20(20) . . . . . . . . subtract 0.20(20) and simplify
x = 20/3 = 6 2/3 . . . . . . . . . divide by 0.60; quarts of 80% solution
(20 -x) = 13 1/3 . . . . . . . . . . amount of 20% solution needed
The teacher should mix 6 2/3 quarts of 80% solution with 13 1/3 quarts of 20% solution.
6x-6
Step-by-step explanation:
add both equations together, then multiply that by 2
2*(2x+3+x-6)
Answer:
False
Step-by-step explanation:
Answer:0.0083
Step-by-step explanation:
Answer:
![5.5](https://tex.z-dn.net/?f=5.5)
Step-by-step explanation:
Mean:
The mean of a data set is commonly known as the average. You find the mean by taking the sum of all the data values and dividing that sum by the total number of data values. The formula for the mean of a population is
![\mu = \frac{{\sum}x}{N}](https://tex.z-dn.net/?f=%5Cmu%20%3D%20%5Cfrac%7B%7B%5Csum%7Dx%7D%7BN%7D)
The formula for the mean of a sample is
![\bar{x} = \frac{{\sum}x}{n}](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%20%3D%20%5Cfrac%7B%7B%5Csum%7Dx%7D%7Bn%7D)
Both of these formulas use the same mathematical process: find the sum of the data values and divide by the total. For the data values entered above, the solution is:
![\frac{55}{10} = 5.5](https://tex.z-dn.net/?f=%5Cfrac%7B55%7D%7B10%7D%20%3D%205.5)