You are given a square ABCD, and midpoints M and N are marked on BC and CD, respectively. Draw AM and BN, which meet at Q. Find
the size of angle AQB.
1 answer:
Step 1: show triangles ABM and BCN are congruent
- AB=BC (sides of square)
- BM=CN (half sides of square)
- angle B = angle C (adjacent sides of square are perpendicular)
=> triangles ABM and BCN are congruent (SAS)
Step: find angle AQB
- angle AQB = QMB+MBQ (exterior angles of a triangle)
= BNC+MBN (corresponding angles of congruent triangles)
= 90 degrees (exterior angle of triangle BNC)
- AB=BC (sides of square)
- BM=CN (half sides of square)
- angle B = angle C (adjacent sides of square are perpendicular)
=> triangles ABM and BCN are congruent (SAS)
Step: find angle AQB
- angle AQB = QMB+MBQ (exterior angles of a triangle)
= BNC+MBN (corresponding angles of congruent triangles)
= 90 degrees (exterior angle of triangle BNC)
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Answer:
- a. image 1
Step-by-step explanation:
<u>Given function:</u>
- f(x) = 2*3ˣ
<u>Plot two points and check which graph has those:</u>
- f(0) = 2*3⁰ = 2
and
- f(1) = 2*3¹ = 6
Points (0, 2) and (1, 6) are correct on the image 1 with blue graph
