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allsm [11]
3 years ago
8

If the length of a pendulum is doubled what will be the change in its time period?

Physics
2 answers:
allsm [11]3 years ago
8 0

If the length is doubled, the period increases by a factor of √2. Doubling the bob 's mass will be half the period

Alex73 [517]3 years ago
4 0

Answer:

If the length is doubled, the period will increase by a factor of √2 .

Explanation:

For Simple Pendulum

T = 2π√(L/g) -----------------(1)

Where T is time period, L is length and g is acceleration due to gravity

Now,

If we double the length,

T = 2π√2L/g

T = √2(2π√(L/g)

From (1), We get

T = √2(T)

So,

If the length is doubled, the period will increase by a factor of √2 .

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An ant crawls along a sidewalk with a velocity of 0.1 m/s in a direction that is 45 degrees relative to the edge of the sidewalk
ahrayia [7]

Answer:

C) 1.0 m

Explanation:

The component of the velocity parallel to the sidewalk is:

vₓ = v cos θ

vₓ = 0.1 m/s cos 45°

vₓ = 0.0707 m/s

The distance traveled after 14 seconds is:

d = vₓ t

d = (0.0707 m/s) (14 s)

d = 0.99 m

Closest answer is C) 1.0 m.

6 0
3 years ago
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A box of Thanksgiving presents slides across a waxy floor at 20m/s. It comes to a stop in 4 seconds. What distance did the box t
mars1129 [50]

Answer:

V = d/t = 20

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6 0
3 years ago
When an exothermic reaction releases thermal energy, this energy is usually_____.
saw5 [17]

Explanation:

A chemical reaction in which heat or energy is released is known as an exothermic reaction.

On the other hand, when two objects are placed together and heat flows from hotter object to colder object then this process is known as conduction. Therefore, energy is dissipated in conduction process.

Since energy released released goes into the atmosphere and is not used anywhere.

Thus, we can conclude that when an exothermic reaction releases thermal energy, this energy is usually not useable to do work and it is dissipated by conduction.

8 0
3 years ago
The body contains many small currents caused by the motion of ions in the organs and cells. Measurements of the magnetic field a
RoseWind [281]

Answer:

270 μA

Explanation:

Use the magnetic field due to long, straight wire and solve for current I.

B= \frac{\mu_0I}{2\pi r}

I= \frac{2\pi r B}{\mu_0}

plug in the values

I= \frac{2\pi(5.40\times10^{-2})\times10\times10^{-6}\times10^{-4}}{4\pi\times10^{-7}}

= 2.7×10^{-4)×10^6

=270 μA

The current that flows in the  heart is 270 μA

8 0
3 years ago
Suppose you pluck a string on a guitar and it produces the note A at a frequency of 440 Hz. Now you press your finger down on th
MAVERICK [17]

Answer:

D. 550 Hz

Explanation:

Frequency for string is given by

f_{} =\frac{v}{2L}

where v is the speed of the wave, L = m is the length

Frequency is inversely proportional to the Length of the string

f \alpha \frac{1}{L} \\

from above relation we can write

\frac{f_{1}}{f_{2}} =\frac{L_{2}}{L_{1}}

The newly shortened string has 4/5 the length of the full string .i,e

\frac{440}{f_{2}} =\frac{\frac{4}{5}L_{1} }{L_{1}}\\f_{2}=\frac{440\times5}{4} \\f_{2}=550 Hz

Hence option D is correct

8 0
3 years ago
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