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allsm [11]
3 years ago
8

If the length of a pendulum is doubled what will be the change in its time period?

Physics
2 answers:
allsm [11]3 years ago
8 0

If the length is doubled, the period increases by a factor of √2. Doubling the bob 's mass will be half the period

Alex73 [517]3 years ago
4 0

Answer:

If the length is doubled, the period will increase by a factor of √2 .

Explanation:

For Simple Pendulum

T = 2π√(L/g) -----------------(1)

Where T is time period, L is length and g is acceleration due to gravity

Now,

If we double the length,

T = 2π√2L/g

T = √2(2π√(L/g)

From (1), We get

T = √2(T)

So,

If the length is doubled, the period will increase by a factor of √2 .

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Answer:

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4 0
2 years ago
A glass rod and a steel rod are of equal length at 0C. At 100C they differ in length by
NeX [460]

The given lengths at 0 °C are 2.5 m

Let l₀ be the given lengths of the glass and steel rods at 0 °C. Let l and l' be the lengths of the glass and steel rods at 100 °C respectively.

From our expression for linear expansivity,

l = l₀ + l₀αΔθ where α = linear expansivity of glass = 0.000008/°C and Δθ = temperature change = θ - θ' where θ = 100 °C and θ' = 0 °C. So, Δθ = 100 °C - 0 °C = 100 °C.

Also,

l' = l₀ + l₀α'Δθ where α' = linear expansivity of steel = 0.000012/°C and Δθ = temperature change = θ - θ' where θ = 100 °C and θ' = 0 °C. So, Δθ = 100 °C - 0 °C = 100 °C.

Since the difference in their lengths at 100 °C = 0.001 m, we have that

l - l' = l₀ + l₀αΔθ - (l₀ + l₀α'Δθ)

l - l' = l₀ + l₀αΔθ - l₀ - l₀α'Δθ)

l - l' = l₀αΔθ - l₀α'Δθ

l - l' = l₀(α- α')Δθ

Making l₀ subject of the formula, we have

l₀ = (l - l')/[(α- α')Δθ]

Substituting the values of the variables into the equation, we have

l₀ = (l - l')/[(α- α')Δθ]

l₀ = 0.001 m/[(0.000008/°C - 0.000012/°C)100 °C.]

l₀ = 0.001 m/[(-0.000004/°C)100 °C.]

l₀ = 0.001 m/-0.0004

l₀ = -2.5 m

Neglecting the negative sign,

l₀ = 2.5 m

So, the given lengths at 0 °C are 2.5 m

Learn more about linear expansion here:

brainly.com/question/14089545

6 0
2 years ago
Use 3rd law to explain how a fish swims through water. Identify the force pairs and draw a diagram.
vovikov84 [41]
Well as the fish swims he pushes the water behind him which in return push him forward
5 0
2 years ago
A student pushes on a 8-kg box with a force of 35 N forward. The force of sliding friction is 10 N backward. What is the acceler
Ne4ueva [31]

Answer:

(35 N - 10 N)/8kg = 3.125 m/s^2

Explanation:

The formula for Force is:

Force = Mass*Acceleration

(Force is equal to Mass times Acceleration)

Since we're told to find the acceleration of the box. We make acceleration the subject of the equation:

Acceleration = Force/Mass

(Acceleration equal to Force divided by Mass)

We know that the force are 35 N forward and 10 N backward, and the weight of the box is 8kg.

= (35 N - 10 N)/8kg

The reason that 35 N minus 10 N is because the 10 N is pushing the box backward.

= 25 N/8kg

= 3.125 m/s^2

Hope it helps :DD

3 0
3 years ago
3. Applying Concepts Explain why a canoe that has hollow, water-
Alekssandra [29.7K]

Answer:

I may be wrong

Explanation:

it it won't collapse because it is like a log logs don't sink when they are in water

5 0
3 years ago
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