1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Hitman42 [59]
3 years ago
15

a lump of putty and a rubber ball have equal mass. both are thrown with equal speed against a wall. the putty sticks to the wall

. the ball bounces back at nearly the same speed with which it hit the wall. which object experiences the greater momentum change?

Physics
2 answers:
RUDIKE [14]3 years ago
5 0
The bouncy ball experiences the greater momentum change.

To understand why, you need to remember that momentum is actually
a vector quantity ... it has a size AND it has a direction too.

The putty and the ball have the same mass, and you throw them
with the same speed.  So, on the way from your hand to the wall,
they both have the same momentum.
Call it " M in the direction toward the wall ".

After they both hit the wall:

-- The putty has zero momentum.
    Its momentum changed by an amount of  M .

-- The ball has momentum of " M in the direction away from the wall ".
    Its momentum changed by an amount of  2M .
fredd [130]3 years ago
4 0

<h3>Rubber ball will experience the greater momentum change than the lump of putty</h3>

\texttt{ }

<h3>Further explanation</h3>

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

\large {\boxed {F = ma }

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

mass of a lump of putty = m

mass of rubber ball = m

initial speed of putty = v

final speed of putty = 0

initial speed of rubber ball = v

final speed of rubber ball = -v

<u>Asked:</u>

the change in momentum = Δp = ?

<u>Solution:</u>

<em><u>Lump of Putty :</u></em>

\Delta p_{putty} = mv_f' - mv_i

\Delta p_{putty} = m(0) - mv

\Delta p_{putty} = - mv

\texttt{ }

<u>Rubber Ball:</u>

\Delta p_{ball} = mv_f' - mv_i

\Delta p_{ball} = m(-v) - mv

\Delta p_{ball} = - 2mv

\texttt{ }

\Delta p_{ball} : \Delta p_{putty} = - 2mv : - mv

\Delta p_{ball} : \Delta p_{putty} = 2 : 1

\Delta p_{ball} = 2\Delta p_{putty}

\Delta p_{ball} > \Delta p_{putty}

From calculation above , we can conclude that rubber ball will experience the greater momentum change than the lump of putty

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Newton's Law of Motion: brainly.com/question/10431582
  • Example of Newton's Law: brainly.com/question/498822

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

\texttt{ }

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

You might be interested in
Please help me pwease
Alisiya [41]

Answer:

Iron

Explanation:  It is by mass the most common element on Earth, right in front of oxygen, forming much of Earth's outer and inner core.

6 0
2 years ago
A fire truck has a searchlight with a resistance of 60 (ohm) which is placed across a 24-V battery. What is the current in this
Mariulka [41]

Answer: 0.4 Amps

Explanation:

Voltage of battery = 24 Volts

Current I = ?

Resistance of searchlight (R)= 60ohms (Ω is the symbol for ohms)

Then, apply the formula for ohms law

Voltage = Current x resistance

i.e V = I x R

24V = I x 60Ω

I = 24V / 60Ω

I = 0.4 Amps (Amps is the unit of current)

Thus, the current in the circuit is 0.4 Amps

3 0
3 years ago
Which of the following tools is used to observe objects that are very far away? A. a anemometer B. a hand lens C. a microscope D
inn [45]

Answer:

D. a telescope

Explanation:

3 0
3 years ago
Read 2 more answers
From the average distance of one of jupiter's moons to jupiter and its orbital period around jupiter, we can determine:
den301095 [7]

Answer: Jupiter's mass

Explanation:

From Kepler's third law:

T^2=\frac{4\pi^2}{GM}a^3

where T is the orbital period of a satellite, a is the average distance of the satellite from the Planet, M is the mass of the planet, G is the gravitational constant.

If the average distance of one of Jupiter's moons to Jupiter and its orbital period around Jupiter is given then mass of the Jupiter can be found:

\Rightarrow M_J=\frac{4\pi^2}{GT_m^2}a_m^3

4 0
3 years ago
Read 2 more answers
Explain why a doctor might not give you any medication if you have a viral disease?
fomenos

Answer:

You never know if the medication could make you worse

Explanation:

5 0
3 years ago
Read 2 more answers
Other questions:
  • A student places a large pot of cold water on a stove and heats it for one minute. Then she takes the pot of water off the burne
    9·1 answer
  • If Earth's obliquity was 157 degrees, would the seasons be more severe, less severe, or about the same?
    15·1 answer
  • Which of the following air conditions would be least likely to have precipitation 10 pts
    14·1 answer
  • Which of the following best demonstrates the effect of static friction? A. A person dropping a ball to the ground. B. A person p
    14·1 answer
  • A scientific idea becomes valid when it is
    11·1 answer
  • A ball is on the end of a rope that is 1.72 m in length. The ball and rope are attached to a pole and the entire apparatus, incl
    12·1 answer
  • Volume of 10 coin is 25ml what is the volume of 1 coin
    10·1 answer
  • A car sets off from the traffic lights. It reaches a speed of 27 m/s in 18 seconds. What is its acceleration?
    10·1 answer
  • What is required for an electromagnet to produce a magnetic field that is
    11·2 answers
  • A child jumps on a trampoline, which of the following causes the child to rise in the air?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!