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Hitman42 [59]
3 years ago
15

a lump of putty and a rubber ball have equal mass. both are thrown with equal speed against a wall. the putty sticks to the wall

. the ball bounces back at nearly the same speed with which it hit the wall. which object experiences the greater momentum change?

Physics
2 answers:
RUDIKE [14]3 years ago
5 0
The bouncy ball experiences the greater momentum change.

To understand why, you need to remember that momentum is actually
a vector quantity ... it has a size AND it has a direction too.

The putty and the ball have the same mass, and you throw them
with the same speed.  So, on the way from your hand to the wall,
they both have the same momentum.
Call it " M in the direction toward the wall ".

After they both hit the wall:

-- The putty has zero momentum.
    Its momentum changed by an amount of  M .

-- The ball has momentum of " M in the direction away from the wall ".
    Its momentum changed by an amount of  2M .
fredd [130]3 years ago
4 0

<h3>Rubber ball will experience the greater momentum change than the lump of putty</h3>

\texttt{ }

<h3>Further explanation</h3>

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

\large {\boxed {F = ma }

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

mass of a lump of putty = m

mass of rubber ball = m

initial speed of putty = v

final speed of putty = 0

initial speed of rubber ball = v

final speed of rubber ball = -v

<u>Asked:</u>

the change in momentum = Δp = ?

<u>Solution:</u>

<em><u>Lump of Putty :</u></em>

\Delta p_{putty} = mv_f' - mv_i

\Delta p_{putty} = m(0) - mv

\Delta p_{putty} = - mv

\texttt{ }

<u>Rubber Ball:</u>

\Delta p_{ball} = mv_f' - mv_i

\Delta p_{ball} = m(-v) - mv

\Delta p_{ball} = - 2mv

\texttt{ }

\Delta p_{ball} : \Delta p_{putty} = - 2mv : - mv

\Delta p_{ball} : \Delta p_{putty} = 2 : 1

\Delta p_{ball} = 2\Delta p_{putty}

\Delta p_{ball} > \Delta p_{putty}

From calculation above , we can conclude that rubber ball will experience the greater momentum change than the lump of putty

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Newton's Law of Motion: brainly.com/question/10431582
  • Example of Newton's Law: brainly.com/question/498822

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

\texttt{ }

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

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Un cuerpo se mueve con MRU a una rapidez de 12 m/s y recorre 240 m; luego, disminuye su ra¬pidez uniformemente a razón de 2 m/s2
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Answer:

29 seconds

Explanation:

First we have a constant speed of 12 m/s and the distance of 240 m, so to find the time we can use the formula:

distance = speed * time

240 = 12 * time1

time1 = 20 seconds

Then, the speed decreases at 2 m/s2 until it reaches 2 m/s. So to find this time, we use this formula:

Final speed = inicial speed + acceleration * time

2 = 12 - 2 * time2

2*time2 = 10

time2 = 5 seconds.

Then, the speed increases from 2 m/s to 22 m/s with an acceleration of 5 m/s2, so we have:

Final speed = inicial speed + acceleration * time

22 = 2 + 5 * time3

5*time3= 20

time3 = 4 seconds

The total time is:

Total time = time1 + time2 + time3 = 20 + 5 + 4 = 29 seconds

7 0
3 years ago
How much heat is given off when 210.0g of water at 0 degrees freezes into ice?
Sergio [31]

In the freezing physical change, when 210.0 g of water a 0 degrees freezes into ice, it gives off 71.0 kJ of heat.

<h3>What is freezing?</h3>

It is a physical change in which liquids give off heat to form solids.

We have 210.0 g of water at 0°C. We can calculate the amount of heat given off when it freezes into ice using the following expression.

Q = ΔH°fus × m

Q = 0.334 kJ/g × 210.0 g = 70.1 kJ

where,

  • Q is the heat released.
  • ΔH°fus is the latent heat of fusion.
  • m is the mass.

In the freezing physical change, when 210.0 g of water a 0 degrees freezes into ice, it gives off 71.0 kJ of heat.

Learn more about freezing here: brainly.com/question/40140

#SPJ1

5 0
2 years ago
Which of the following temperature readings is the coldest?
djverab [1.8K]

Answer: K

Explanation:

From the temperature readings given, we should note that 0°F is thesame as 32°C. Therefore, 0°C is colder than 0°F.

We should note that at 0K which is written as K, it is the coolest and it is often called the absolute zero because at this degree, there can't be anything that's colder.

Therefore, the answer is K

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