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3 years ago

5

What is the square root of 850

1 answer:

Ilya [14]3 years ago

8 0

The square root of 850 is about 29.15

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Samuel is running a 3-mile race. He would like to finish the race in under 33 minutes. He has already run for 10.5 minutes.

dezoksy [38]

he should have covered 0.95-mile

8 0

2 years ago

Find the distance between A (2,6) and N (5, 10). Round<br> To the nearest tenth

Svetllana [295]

Answer:

5.0 units

Step-by-step explanation:

The distance between two points can be expressed in formula of:

$\displaystyle{d = \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}}$

Determine:

$\displaystyle{(x_2,y_2)}$ is (5,10).
$\displaystyle{(x_1,y_1)}$ is (2,6).

Therefore, substitute in the formula to find distance:

$\displaystyle{d = \sqrt{\left(5-2\right)^2+\left(10-6\right)^2}}\\\\\displaystyle{d = \sqrt{3^2+4^2}}\\\\\displaystyle{d = \sqrt{9+16}}\\\\\displaystyle{d = \sqrt{25}}\\\\\displaystyle{d = 5}$

Therefore, the distance between two points is 5.0 units.

7 0

1 year ago

Mathew rolls a number cube labeled with the numbers 1−6. He then flips a fair coin. What is the probability that he rolls a 4 an

KATRIN_1 [288]

Answer:

0.083

Step-by-step explanation:

Numbers of Cube = 6

Faces on coins = 2

Therefore, The total outcomes = $6 \times 2 = 12$

Now the favourable outcome that he rolls a 4 & flips a head = 1

The probability that he rolls a 4 & flips a head = 1

$\frac{Favourable \: Outcome}{Total \: Outcome}$

=> The probability that he rolls a 4 & flips a head = $\frac{1}{2} = 0.83333/ approx. 0.83$

Therefore, The probability that he rolls a 4 & flips a head = 0.083

7 0

3 years ago

Read 2 more answers

Simplify √ 20 x 8 y 9 to the form a √ b .

Contact [7]

Answer:

Juanita dissolves 46 g of MgBr2 (molar mass: 184.11 g/mol) in 0.5 kg of distilled water. What is the molality of the solution?

6 0

3 years ago

The function f(x) = x2 + 6x + 3 is transformed such that g(x) = f(x − 2). Find the vertex of g(x).

garri49 [273]

Answer:

(-1,-6)

Step-by-step explanation:

$f(x)=x^2+6x+3$

$g(x)=f(x-2)$

$g(x)=(x-2)^2+6(x-2)+3$ (Replaced x in f with (x-2))

$g(x)=x^2-4x+4+6x-12+3$ (Used $(x+b)^2=x^2+2bx+b^2$ and distributive property)

$g(x)=x^2-4x+6x+4-12+3$ (Gathered like terms)

$g(x)=x^2+2x-5$ (Simplified)

The vertex of a parabola occurs at $(\frac{-b}{2a},g(\frac{-b}{2a})$ .

Let's find $\frac{-b}{2a}$ first.

$\frac{-2}{2(1)}=-1$

Now we can obtain $g(\frac{-b}{2a})$ which is $g(-1)$ in this case:

$g(x)=x^2+2x-5$

$g(-1)=(-1)^2+2(-1)-5$

$g(-1)=1-2-5$

$g(-1)=-1-5$

$g(-1)=-6$ .

The vertex is (-1,-6).

6 0

3 years ago