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sukhopar [10]
3 years ago
13

5. Name three sets of supplementary angles.andandand​

Mathematics
1 answer:
jarptica [38.1K]3 years ago
8 0
87 and 93
45 and 135
74 and 106
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Which number produces a rational number when added to 1/5?
Ainat [17]

Answer:

The answer is -2/3.

8 0
3 years ago
Use the graph to determine the function's domain and range. Explain your answer.
mixas84 [53]
The domain is defined as  all the possible x values. The graph extends to the left and to the right without bounds  so the domain is All Real Values of x.
It can also be written as   (-∞, ∞)  This is called interval notation.

Note that  the minimum value of f(x)  is -4  so the range is [-4, ∞).   (All real values of y equal to or greater than -4)

3 0
3 years ago
Maya has some books she gives away 26 now she has 36 how many did she start with?​
poizon [28]

Answer:

62

Step-by-step explanation:

26+36=x

x=62

4 0
3 years ago
Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
3 years ago
A circle has a radius of 6. An arc in this circle has a central angle of 48 degress. What is the length of the arc?
notsponge [240]

Answer: 1.6\pi

Step-by-step explanation:

If a circle has a radius of 6, then the perimeter of the circle is 12pi, or about 37.68.  A circle has 360 degrees.  Thus, the arc takes up 48/360 of the circle.  Thus, simply multiply \frac{48}{360} * 12\pi to get 5.024 or 1.6pi.

Hope it helps <3

3 0
3 years ago
Read 2 more answers
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