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julia-pushkina [17]
2 years ago
10

Hi guys can y’all help me with this problem? i’m stuck :p

Mathematics
2 answers:
wlad13 [49]2 years ago
5 0
Heyy,i believe it’s the last option:)
Thepotemich [5.8K]2 years ago
3 0
The first one is the correct answer
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For the equation --4y = 8x, what is the constant of variation?
larisa86 [58]

Answer: 1) B is correct, constant of variation is -2.

Step-by-step explanation:

1)

Direct variation states that a relationship between the two variables. we say y varies directly as x

i.e,  or y =kx.................[1] ;  where k is the constant of variation.

Given the equation:

Divide both sides by -4 we get;

Simplify:

            .......[2]

On comparing equation [2] with [1] we get;

k = -2

6 0
3 years ago
A study examined the alertness benefits of higher caffeine intake. In the study, the researchers investigated the link between d
Katyanochek1 [597]

Answer: B. The data represent a sample since the data are a subset of units.

Step-by-step explanation:

  • A population is the largest group of entire observations that can be made during a study.
  • A sample is a finite subset of the population that represents the entire population.

Here,

Population = Participants for the study were those who used a popular social networking Web site.

Since the entire data for the "persons used a popular social networking Web site" is not possible.

There have been taken a sample of them.

∴ Correct answer is B. The data represent a sample since the data are a subset of units.

3 0
3 years ago
Morris has 2 3/4 gallons of ice tea. He gives 3/7 of it to her friend. How many gallons of ice tea does Morris have left?
lara31 [8.8K]

Answer:

2 \frac{9}{28} gallons of ice tea is left with Morris

Step-by-step explanation:

Morris has 2 3/4 gallons of ice tea. He gives 3/7 of it to her friend.

Morris has 2 3/4 gallons of ice tea

2\frac{3}{4}= \frac{2*4+3}{4}=\frac{11}{4}

He gives 3/7 of it to her friend.

To find how many gallons of ice tea does Morris have left , we subtract 3/7 from 11/4

\frac{11}{4}- \frac{3}{7}

Make the denominators same

\frac{11*7}{4*7}- \frac{3*4}{7*4}

\frac{77}{28}- \frac{12}{28}

\frac{65}{28}

\frac{65}{28} = 2 \frac{9}{28}

7 0
3 years ago
NO LINKS!! Please help me with these graphs​
Stella [2.4K]

Answer:

  • square: 9 square units
  • triangle: 24 square units

Step-by-step explanation:

Using a suitable formula the area of a polygon can be computed from the coordinates of its vertices. You want the areas of the given square and triangle.

<h3>Square</h3>

The spreadsheet in the first attachment uses a formula for the area based on the given vertices. It computes half the absolute value of the sum of products of the x-coordinate and the difference of y-coordinates of the next and previous points going around the figure.

For this figure, going to that trouble isn't needed, as a graph quickly reveals the figure to be a 3×3 square.

The area of the square is 9 square units.

<h3>Triangle</h3>

The same formula can be applied to the coordinates of the vertices of a triangle. The spreadsheet in the second attachment calculates the area of the 8×6 triangle.

The area of the triangle is 24 square units.

__

<em>Additional comment</em>

We have called the triangle an "8×6 triangle." The intention here is to note that it has a base of 8 units and a height of 6 units. Its area is half that of a rectangle with the same dimensions. These dimensions are readily observed in the graph of the vertices.

7 0
1 year ago
Pratap puri rowed 10 miles down a river in 2 ​hours, but the return trip took him 2 and one half hours. Find the rate pratap can
N76 [4]

Answer:

<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>

Step-by-step explanation:

Pratap Puri rowed 10 miles down a river in 2 ​hours, but the return trip took him 2.5 hours.

We know that, Speed = \frac{Distance}{Time}

So, the <u>speed of Pratap with the current</u> will be:  (\frac{10}{2})miles/hour = 5 miles/hour

and the <u>speed of Pratap against the current</u> will be:  (\frac{10}{2.5})miles/hour = 4 miles/hour.

Suppose, the rate of Pratap in still water is x and the rate of current is y.

So, the equations will be........

x+y= 5 .............................. (1)\\ \\ x-y=4 .............................. (2)

Adding equation (1) and (2) , we will get......

2x=9\\ \\ x=\frac{9}{2}= 4.5

Now, plugging this x=4.5 into equation (1), we will get.....

4.5+y=5\\ \\ y=5-4.5 =0.5

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.

6 0
3 years ago
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