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777dan777 [17]
3 years ago
8

Choose the correct answer from the list. No answer is used twice. Not all of the answers will be used. The electron carrier, NAD

H, is derived from the ____________ vitamin. In aerobic organisms, the ultimate acceptor of electrons is ____________. In aerobic metabolism, the carbon atoms in fuels ultimately become ________. The small organic compounds, ____________, are required in the diet of higher organisms and are components of coenzymes. ____________: This compound serves as an acyl carrier in metabolism. A. oxygen B. coenzyme A C. minerals D. niacin E. NADPH F. CO2 G. riboflavin H. ATP I. vitamins
Chemistry
1 answer:
adelina 88 [10]3 years ago
7 0

Answer:

The electron carrier, NADH, is derived from niacin vitamin.

In aerobic organisms, the ultimate acceptor of electrons is oxygen.

In aerobic metabolism, the carbon atoms in fuels ultimately become CO₂.

The small organic compounds, vitamins are required in the diet of higher organisms and are components of coenzymes.

Coenzyme A This compound serves as an acyl carrier in metabolism.

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How much (in mL) 12.1 M solution of hydrochloric acid would be required to make 500 mL of a 2.5 M solution
victus00 [196]

Answer:

Volume of the concentrated solution, which is needed is 103.30 mL

Explanation:

Let's apply the formula for dilutions to solve the problem

Conc. Molarity . Conc. volume = Dil. Molarity . Dil volume

12.1 M . Conc. volume = 2.5 M . 500 mL

Conc. volume = (2.5 M . 500 mL) / 12.1M

Conc. volume = 103.30 mL

6 0
4 years ago
Calculate the pH of 1.00 L of the buffer 0.95 M CH3COONa/0.92 M CH3COOH before and after the addition of the following species.
natima [27]

Answer: (a) pH = 4.774, (b) pH = 4.811 and (c) pH = 4.681

Explanation: (a) pH of the buffer solution is calculated using Handerson equation:

pH=pKa+log(\frac{base}{acid})

pKa for acetic acid is 4.76. concentration of base and acid are given as 0.95M and 0.92M. Let's plug in the values in the equation and calculate the pH of starting buffer.

pH=4.76+log(\frac{0.95}{0.92})

pH = 4.76 + 0.014

pH = 4.774

(b) When 0.040 mol of NaOH (strong base) are added to the buffer then it reacts with 0.040 mol of acetic acid and form 0.040 mol of sodium acetate.

Original buffer volume is 1.00 L. So, the original moles of sodium acetate will be 0.95 and acetic acid will be 0.92.

moles of acetic acid after addition of NaOH = 0.92 - 0.040 = 0.88

moles of sodium acetate after addition of NaOH = 0.95 + 0.040 = 0.99

Let's again plug in the values in the Handerson equation:

pH=4.76+log(\frac{0.99}{0.88})

pH = 4.76 + 0.051

pH = 4.811

(c) When 0.100 mol of HCl are added then it reacts with exactly 0.100 moles of sodium acetate(base) and form 0.100 moles of acetic acid(acid).

so, new moles of acetic acid = 0.92 + 0.100 = 1.02

new moles of sodium acetate = 0.95 - 0.100 = 0.85

Let's plug in the values in the equation:

pH=4.76+log(\frac{0.85}{1.02})

pH = 4.76 - 0.079

pH = 4.681

5 0
4 years ago
Discard the water from the first step and re-fill the tall drinking water glass with the chilled water. Then slowly pour a small
inna [77]

Answer:

The hot water remains at the top of chilled water.

Explanation:

The hot water remains at the top of chilled water because hot water has less denser as compared to chilled water. Due to higher density of chilled water, it remains at the bottom due to its greater mass while on the other hand, the hot freshwater goes upward and spreads at the top of the chilled water due to lower mass so when the hot water is added to the chilled water, hot water remains at the top.

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3 years ago
Which situation aUggeata that an experlment han rellable renultn?
Crazy boy [7]

Answer:

Shiny like a limousine

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Don't front, no need ty67t6767

Explanation:

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3 years ago
O que acontece com a perspiração celular se, pro algum motivo, uma pessoa foi impedida de executar a respiração pulmonar?
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Answer:

I wish I spoke this languge.

Explanation:

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3 years ago
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