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garri49 [273]
2 years ago
10

Which Cl isotope should we use to get the atomic mass of the element Cl?

Chemistry
1 answer:
Sati [7]2 years ago
5 0

Answer:

i think it's B CI-35 only

Explanation:

hope this helps

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Help please Thank You so much!
Irina18 [472]
If you count the number of electrons (small dots), you have the atomic number. In this case you have 11 so this atom is a sodium atom. Sodium has 1 valence electron (electron on the outer shell) and chlorine has 7. This means that if sodium gave one electron away and chlorine would obtain one electron, they would both have the (ideal) noble gas conformation (full outer shell).
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3 years ago
Which colour would you expect ekasilicon to be
LiRa [457]

Answer:

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Explanation:

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A balloon is filled with 3.8 l of helium gas at stp. approximately how many moles of helium are contained in the balloon?
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3 years ago
Read 2 more answers
Copper (II) sulfate pentahydrate may be heated to drive off the water of hydration. If 5 g of water are produced, what was the o
____ [38]

Answer:

13.9g of CuSO4•5H2O

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CuSO4•5H2O → CuSO4 + 5H2O

Next, we shall determine the mass of CuSO4•5H2O heated and the mass of H2O produced from the balanced equation.

This is illustrated below

Molar mass of CuSO4• 5H2O = 63.5 + 32 + (16x4) + 5(2x1 + 16)

= 63.5 + 32 + 64 + 5(18) = 249.5g/mol

Mass of CuSO4•5H2O from the balanced equation = 1 x 249.5 = 249.5g

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O from the balanced equation = 5 x 18 = 90g

From the balanced equation above,

249.5g of CuSO4•5H2O produced 90g of H2O.

Now, we can determine the mass of CuSO4•5H2O needed to produce 5g of H2O. This can be achieved as shown below:

From the balanced equation above,

249.5g of CuSO4•5H2O produced 90g of H2O.

Therefore, Xg of CuSO4•5H2O will produce 5g of H2O i.e

Xg of CuSO4•5H2O = (249.5 x 5)/90

Xg of CuSO4•5H2O = 13.9g

Therefore, 13.9g of CuSO4•5H2O is needed to produce 5g of H2O.

6 0
3 years ago
Can anybody help me with these 2 ohms law
Fynjy0 [20]

Answer:

1

yywhhwhwhwysuiwjwcwcwfwhwuwiwioowow

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3 years ago
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