Answer:
What do you need help with?
Step-by-step explanation:
Answer:
Given:
n = 15
c = 95% = 0.95
Let us assume:
α = 0.05
Determine the difference in value of each pair.
→See attached for the table←
→See attached for the for the workings←
Result
a) There is sufficient evidence to reject the claim that the two methods provide the same mean value for natural vibration frequency.
b) (-10.9646, -0.0068)
Answer:
C (The lower left one)
Step-by-step explanation:
I saw that the vertex was equal to (-1,1) and that is the only answer that makes sense
So
a be first term and d be common difference
- a+a+2d+a+4d+a+6d+a+9d=17
- 5a+21d=17--(1)
And
- a+d+a+3d+a+5d+a+7d+a+9d=15
- 5a+25d=15--(2)
Eq(1)-Eq(2)
Put in second one
- 5a+25d=15
- a+5d=3
- a+5/2=15
- a=15-5/2
- a=25/2