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Firlakuza [10]
1 year ago
9

Determine if the following infinite series converges or diverges

Mathematics
2 answers:
stiks02 [169]1 year ago
7 0

The series diverges by the comparison test.

We have for large enough k,

\displaystyle \frac{k^3}{k^4+10} \approx \frac{k^3}{k^4} = \frac1k

so that

\displaystyle \sum_{k=0}^\infty \frac{k^3}{k^4+10} = \frac1{10} + \sum_{k=1}^\infty \frac{k^3}{k^4+10} \approx \frac1{10} + \sum_{k=1}^\infty \frac1k

and the latter sum is the divergent harmonic series.

Mandarinka [93]1 year ago
6 0

Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.

<h3>How do we verify if a sequence converges of diverges?</h3>

Suppose an infinity sequence defined by:

\sum_{k = 0}^{\infty} f(k)

Then we have to calculate the following limit:

\lim_{k \rightarrow \infty} f(k)

If the <u>limit goes to infinity</u>, the sequence diverges, otherwise it converges.

In this problem, the function that defines the sequence is:

f(k) = \frac{k^3}{k^4 + 10}

Hence the limit is:

\lim_{k \rightarrow \infty} f(k) = \lim_{k \rightarrow \infty} \frac{k^3}{k^4 + 10} = \lim_{k \rightarrow \infty} \frac{k^3}{k^4} = \lim_{k \rightarrow \infty} \frac{1}{k} = \frac{1}{\infty} = 0

Hence, the infinite sequence converges, as the limit does not go to infinity.

More can be learned about convergent sequences at brainly.com/question/6635869

#SPJ1

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