Answer:
Step-by-step explanation:
Let x be the variable of the required quadratic equation.
are the roots of the required quadratic equation.
are factors of the required quadratic equation.
is the required quadratic equation
Let me show u one in detail.
First we have to find the common ratio. We do this by dividing the second term by the first term.
ur first problem...
12/3 = 4...so the common ratio is 4
now we use the formula
an = a1 * r^(n-1)
n = term u want to find = 15
a1 = first term = 3
r = common ratio = 4
now we sub
a15 = 3 * 4^(15 - 1)
a15 = 3 * 4^14
a15 = 3 * 268435456
a15 = 805,306,368 <== ur 15th term
thats all there is to it...and, of course, u can always look on the internet for a geometric sequence calculator...to check urself...lol
Answer:
27 =x
Step-by-step explanation:
We can use the triangle angle bisector theorem
x+8 2x-5
-------- = ----------
10 14
Using cross products
14 (x+8) = 10 (2x-5)
Distribute
14x+112 = 20x -50
Subtract 14x from each side
14x-14x+112 = 20x-14x -50
112 = 6x - 50
Add 50 to each side
112+50 = 6x+50
162 = 6x
Divide by 6
162/6 = 6x/6
27 =x
Answer:
(x - 2)(3x^2 + 5)
Step-by-step explanation:
All four terms here have 3 as a factor. Factor out 3:
3x^(3)-6x^(2)+15x-30 => 3(x^3 - 2x^2 + 5x - 10)
The last two terms can be rewritten as 5(x - 2). The first two terms can be rewritten as 3x^2(x - 2). So (x - 2) is a factor of 3(x^3 - 2x^2 + 5x - 10). We get:
3x^2(x - 2) + 5(x - 2) = (x - 2)(3x^2 + 5)
So now it is an division problem, I got out my calcuator for this.
The numarical eqpression is 212212 / 5. It said 42442.4. It is in simpelest form!
I would be thankful for brainliest!