Question

Chris, Devin, Bradley and Mitchell are all basketball players, and the total of their ages is 104. Chris is twice as old as Bradley; Devin is eight years older than Bradley, and Mitchell is eight years older than Devin.

Answer 1

Chris is twice as old as Bradley: C = 2B

Devin is eight years older than Bradley: D = B + 8

Mitchell is eight years older than Devin: M = B + 8 + 8

Bradley: B = B

$C + D + M + B = 104$

Plug in the values:

$(2B) + (B + 8) + (B + 8 + 8) + (B) = 104$

--> $5B + 24 = 104$

Subtract 24 from both sides.

5B = 104 - 24

5B = 80

B = $\frac{80}{5}$

B = 16

Plug in the values to know the age of each player:

Chris: 2(16) Chris is 32 years old.

Devin: (16) + 8 Devin is 24 years old.

Mitchell: (16) + 8 + 8 Mitchell is 32 years old.

Bradley is sixteen years old.

To check your work, add up all of their ages: 2(32) + 24 + 16 = 104

Hope this was helpful.