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IRISSAK [1]
4 years ago
5

Why does it make sense that if an atom loses electrons, it is left with a positive charge?

Chemistry
1 answer:
rosijanka [135]4 years ago
5 0
Electrons are negatively charged. If you remove negative particles, the leftover atom is positive and positive is really just another word for "less negative".
You might be interested in
When two atoms of element Y combine, Y2 molecule is formed.
Liula [17]

Answer:

chemical bond

Explanation:

because this is the only bond used in chemical reactions just like molecules of atoms are combined by this bond

5 0
3 years ago
How many molecules of n2 are in a 200.0 ml container at 780 mmhg and 135∘c?
Neporo4naja [7]
By  use  of  ideal  gas  equation   PV=  nRT     where  n  is  the  number  of  moles,P =  pressure, V   =  volume,  R=  gas  constant  (0.08206 L. atm/ mol.k)     ant  T  is  the  temperature,  

to  calculate  the  number  of  moles(n) =PV/RT

convert  ml  to L,  that  is  200/1000= 0.2  L

convert  mmHg  to  atm,  that  is  780mm hg  x  1atm/  760  mm  hg=  1.026  atm

convert  temperature  to   kelvin,  that  is 135  +273=  408  k
n  is  therefore=  (0.2  x   1.026)/ ( 0.08206  x   408)=  6.129  x10^-3   moles

from  avogadro  constant    1moles  =  6.02  x10^23  molecules   what  about  6 .129  x10^-3  moles

= ( 6.02  x10^23)  x (6.129 x10^-3)/  1mole =  3.69  x10^21  molecules
8 0
3 years ago
5/3 * 2/3 what's the answer
Contact [7]
5 x 2 = 10

3 x 3 = 9

10/9, or 1 1/9 is your answer

hope this helps
6 0
3 years ago
A spring with constant 50 N/m is stretch 0.5 m. How much EPE does it have? A. 25 J B. 12.5 J C. 50 J D. 6.25 J
Step2247 [10]

Answer:

D. 6.25 J

Explanation:

  • EPE = 1/2*k*(Δx)²

∴ k = 50 N/m

∴ Δx = 0.5 m

⇒ EPE = 1/2*50 N/m*(0.5m)²

⇒ EPE = 6.25 N.m = 6.25 J

4 0
3 years ago
Calculate the minimum mass of sulfuric acid that could be left over by the chemical reaction. Be sure your answer has the correc
REY [17]

Full Question:

Aqueous sulfuric acid H2SO4 will react with solid sodium hydroxide NaOH to produce aqueous sodium sulfate Na2SO4 and liquid water H2O. Suppose 94g of sulfuric acid is mixed with 49.9g of sodium hydroxide. Calculate the minimum mass of sulfuric acid that could be left over by the chemical reaction. Be sure your answer has the correct number of significant digits.

Answer:

32.8725g

Explanation:

First thing's first, we write out the balanced chemical equation;

2NaOH + H2SO4 --> Na2SO4 + 2H2O

The question hints that sulphuric acid would be in exess by asking to calculate the minium mass that would be left over.

We proceed by calculatng the amount of sulphuric acid that would react with  49.9g of sodium hydroxide.

From the reaction,

2 moles of NaOH reacts with 1 mole of H2SO4.

Calculate moles of sodium hydroxide:

Molar mass of NaOH= 40.0 g/mol

Mass of NaOH = 53 g

moles = Maass /  Molar mass = 1.2475

This means 1.2475 would react with x number of moles;

2 = 1

1.2475 = x

x = 1.2475 / 2 = 0.62375

Mass of Sulphuric acid reacted = moles * molar mass = 0.62375 * 98 = 61.1275g

Mimium mass of left over = 94 - 61.1275g = 32.8725g

4 0
3 years ago
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