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Katen [24]
3 years ago
5

How many molecules of n2 are in a 200.0 ml container at 780 mmhg and 135∘c?

Chemistry
1 answer:
Neporo4naja [7]3 years ago
8 0
By  use  of  ideal  gas  equation   PV=  nRT     where  n  is  the  number  of  moles,P =  pressure, V   =  volume,  R=  gas  constant  (0.08206 L. atm/ mol.k)     ant  T  is  the  temperature,  

to  calculate  the  number  of  moles(n) =PV/RT

convert  ml  to L,  that  is  200/1000= 0.2  L

convert  mmHg  to  atm,  that  is  780mm hg  x  1atm/  760  mm  hg=  1.026  atm

convert  temperature  to   kelvin,  that  is 135  +273=  408  k
n  is  therefore=  (0.2  x   1.026)/ ( 0.08206  x   408)=  6.129  x10^-3   moles

from  avogadro  constant    1moles  =  6.02  x10^23  molecules   what  about  6 .129  x10^-3  moles

= ( 6.02  x10^23)  x (6.129 x10^-3)/  1mole =  3.69  x10^21  molecules
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Answer:

964ug

Explanation:

The problem here involves converting from one unit to another.

 We are to convert from ounces to micrograms.

                                    1ug  = 1 x 10⁻⁶g

                                    1oz  = 28.35g

       

So we first convert to grams from oz then take to ug:

 Solving:

                    1oz  = 28.35g

             3.4 x 10⁻⁵oz  will then give  3.4 x 10⁻⁵ x 28.35 = 9.64  x 10⁻⁴g

So;

                    1 x 10⁻⁶g    = 1ug

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2 years ago
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3 years ago
Read 2 more answers
A student used 1.168g of an unknown weak acid and titrated it against 28.75 mL of 0.105M NaOH to reach the equivalence point. Wh
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Answer:

The molar mass of the unknown acid is 386.8 g/mol

Explanation:

Step 1: Data given

Mass of the weak acid = 1.168 grams

volume of NaOH = 28.75 mL = 0.02875 L

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Since we only know 1 equivalence point, we suppose the acid is monoprotic

Step 2: Calculate moles NaOH

Moles NaOH = molarity NaOH * volume NaOH

Moles NaOH = 0.105 M * 0.02875 L

Moles NaOH = 0.00302 moles

We need 0.00302 moles of weak acid to neutralize the NaOH

Step 3: Calculate molar mass of weak acid

Molar mass = mass / moles

Molar mass = 1.168 grams / 0.00302 moles

Molar mass = 386.8 g/mol

The molar mass of the unknown acid is 386.8 g/mol

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