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Katen [24]
3 years ago
5

How many molecules of n2 are in a 200.0 ml container at 780 mmhg and 135∘c?

Chemistry
1 answer:
Neporo4naja [7]3 years ago
8 0
By  use  of  ideal  gas  equation   PV=  nRT     where  n  is  the  number  of  moles,P =  pressure, V   =  volume,  R=  gas  constant  (0.08206 L. atm/ mol.k)     ant  T  is  the  temperature,  

to  calculate  the  number  of  moles(n) =PV/RT

convert  ml  to L,  that  is  200/1000= 0.2  L

convert  mmHg  to  atm,  that  is  780mm hg  x  1atm/  760  mm  hg=  1.026  atm

convert  temperature  to   kelvin,  that  is 135  +273=  408  k
n  is  therefore=  (0.2  x   1.026)/ ( 0.08206  x   408)=  6.129  x10^-3   moles

from  avogadro  constant    1moles  =  6.02  x10^23  molecules   what  about  6 .129  x10^-3  moles

= ( 6.02  x10^23)  x (6.129 x10^-3)/  1mole =  3.69  x10^21  molecules
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