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hram777 [196]
3 years ago
8

How many moles of MgS2O3 are in 223 g of the compound

Chemistry
2 answers:
KengaRu [80]3 years ago
6 0
1.63 moles since 1 mole is equal to 136.4332 grams
Ivenika [448]3 years ago
5 0
<span>1.73g </span><span>molecular</span>∛<span> weight of MgSO3 = 104.3682 g/mol </span>
<span>181 g / 104.3682 g/mol </span>
<span>= 1.73 g</span>
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Water flows from the bottom of a large tank where the pressure is 100 psig through a pipe to a turbine which produces 5.82 hp. T
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Explanation:

Bernoulli equation for the flow between bottom of the tank and pipe exit point is as follows.

   \frac{p_{1}}{\gamma} + \frac{V^{2}_{1}}{2g} + z_{1} = \frac{p_{2}}{\gamma} + \frac{V^{2}_{2}}{2g} + z_{2} + h_{f} + h_{t}

    \frac{(100 \times 144)}{62.43} + 0 + h[tex] = [tex]\frac{(50 \times 144)}{(62.43)} + \frac{(70)^{2}}{2(32.2)} + 0 + 40 + 60

                          h = \frac{(50 \times 144)}{(62.43)} + \frac{(70)^{2}}{2(32.2)} + 40 + 60 - \frac{(100 \times 144)}{(62.43)}

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Hence, formula to calculate theoretical power produced by the turbine is as follows.

                                 P = mgh

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                                     = 6076 lb.ft/s

                                     = 11.047 hp

Efficiency of the turbine will be as follows.

                \eta_{t} = \frac{P_{actual}}{P_{theoretical}} × 100%

                                = \frac{5.82}{11.047} \times 100%                      

                                = 52.684%

Thus, we can conclude that the efficiency of the turbine is 52.684%.

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