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4 years ago

How many moles of MgS2O3 are in 223 g of the compound

Chemistry

2 answers:

KengaRu [80]4 years ago

6 0

1.63 moles since 1 mole is equal to 136.4332 grams

Ivenika [448]4 years ago

5 0

1.73g molecular∛ weight of MgSO3 = 104.3682 g/mol 
181 g / 104.3682 g/mol 
= 1.73 g

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where,

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$k$ is proportionality constant i.e. Henry's constant.

$P_g$ is pressure of the gas.

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$P_g = 0.13 bar$ (given)

Substituting the values,

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To convert $mole/kg$ to $g/kg$ :

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Now for converting into $ppm$ :

Since, $1 ppm = 0.001 g/kg$

So, $56.784\times 1000 = 56784 ppm$ .

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