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horsena [70]
3 years ago
14

A spring with constant 50 N/m is stretch 0.5 m. How much EPE does it have? A. 25 J B. 12.5 J C. 50 J D. 6.25 J

Chemistry
1 answer:
Step2247 [10]3 years ago
4 0

Answer:

D. 6.25 J

Explanation:

  • EPE = 1/2*k*(Δx)²

∴ k = 50 N/m

∴ Δx = 0.5 m

⇒ EPE = 1/2*50 N/m*(0.5m)²

⇒ EPE = 6.25 N.m = 6.25 J

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andreev551 [17]

The question is incomplete, here is the complete question:

The rate of certain reaction is given by the following rate law:

rate=k[H_2]^2[I_2]^2

At a certain concentration of H_2 and I_2, the initial rate of reaction is 4.0 × 10⁴ M/s. What would the initial rate of the reaction be if the concentration of

Answer : The initial rate of the reaction will be, 1.0\times 10^4M/s  

Explanation :

Rate law expression for the reaction:

rate=k[H_2]^2[I_2]^2

As we are given that:

Initial rate = 4.0 × 10⁴ M/s

Expression for rate law for first observation:

4.0\times 10^4=k[H_2]^2[I_2]^2 ....(1)

Expression for rate law for second observation:

R=k(\frac{[H_2]}{2})^2[I_2]^2 ....(2)

Dividing 2 by 1, we get:

\frac{R}{4.0\times 10^4}=\frac{k(\frac{[H_2]}{2})^2[I_2]^2}{k[H_2]^2[I_2]^2}

\frac{R}{4.0\times 10^4}=\frac{1}{4}

R=1.0\times 10^4M/s

Therefore, the initial rate of the reaction will be, 1.0\times 10^4M/s

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determine the type of the following chemical reaction: Mg(s) + 2HCl(aq)——-> H2(g) + MgCl2(aq) a. single replacement reaction
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Answer:

a. single replacement reaction

Explanation:

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Answer:

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Explanation:

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So they do alter the path of the reaction where the free energy change (or activation energy) is low then the non enzymatic pathway.

Thus the statement

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Enzyme function is dependent on the pH and temperature of the reaction environment: true

This is also true that

Enzyme activity can be inhibited if the enzyme is bound by a noncompetitive inhibitor.

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