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yawa3891 [41]
3 years ago
7

The function f(x)= square root of x is translated using the rule (x, y) → (x – 6, y + 9) to create A(x). Which expression descri

bes the range of A(x)?
Mathematics
1 answer:
Alex73 [517]3 years ago
4 0

The function f(x)=\sqrt{x} is translated according to the rule

(x,y)\rightarrow (x-6,y+9).

This translation is translation 6 units to the left and 9 units up.

1. Translation of the function f(x)=\sqrt{x} 6 units to the left gives you the function g(x)=\sqrt{x+6}.

2. Translation of the function g(x)=\sqrt{x+6} 9 units up gives you the function A(x)=\sqrt{x+6}+9.

The domain of the function A(x) is [-6,\infty), then the range of the function A(x) is [9,\infty).

Answer: [9,\infty).

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