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Serhud [2]
4 years ago
13

Can someone please help

Mathematics
1 answer:
Rudiy274 years ago
6 0

It is B or 2. Hope this helps


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In the diagram below, BC is an altitude of ABD. To the nearest whole unit, what is the length of CD?
sergiy2304 [10]
For the answer to the question above, I'll show my solution on how you can solve your problem.
AC² + BC² = AB² 
<span>5² + 12² = AB² </span>
<span>25 + 144 = AB² </span>
<span>169 = AB² </span>
<span>13 = AB </span>

<span>Triangle ABC is proportional to triangle ADB. </span>

<span><u>AC </u>= <u>AB </u></span>
<span>AB    AD </span>

<span><u>5</u> = <u>13 </u></span>
<span>13  AD </span>

<span>5AD = 169 </span>

<span>AD = 169/5 </span>

<span>AD = 33.8 </span>

<span>AD = AC + CD </span>

<span>33.8 = 5 + CD 
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<span>CD = 28.8 </span>
8 0
3 years ago
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Show that (a - b)+(b-c)+(c -a)3 = 3 (a - b) (b -c) (c-a)​
nikdorinn [45]

Answer:

I think that it should be

{(a - b)}^{3}  +  {(b - c)}^{3}  +  {(c - a)}^{3}  = 3(a - b)(b - c)(c - a)

Step-by-step explanation:

Here,

we take , a - b = A,b-c = B , c - a= C

A+B+C = 0

we know that,

{a}^{3}  +  {b}^{3}  +  {c}^{3}   - 3abc = (a + b + c)(  {a}^{2}  +  {b}^{2}  +  {c}^{2}  - ab - bc - ca)

Here , A+B+C = 0

so,

A^3 +B^3 + C^3 = 3 ABC

now we put the values

{(a - b)}^{3}  +  {(b - c)}^{3}  +  {(c - a)}^{3}  = 3(a - b)(b - c)(c - a)

I am done .

4 0
4 years ago
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What is the value x ?
34kurt

Answer:

x= 62

Step-by-step explanation:

The value of a triangle is 180 degrees.

68.5+49.5= 118

180-118= 62 degrees

7 0
3 years ago
The sum of the squares of the digits of a positive two-digit number is 20, and the tens digit is 2 more than the units digit. fi
NISA [10]
The numbers are 2 and 4
6 0
3 years ago
The table below represents the distance of an airplane from its destination as a function of time:
Jlenok [28]
\bf \begin{array}{ccllll}&#10;time(hours)&distance(miles)\\&#10;-----&-------\\&#10;0&2700\\&#10;1&2160\\&#10;2&1620\\&#10;3&1080\\&#10;4&540&#10;\end{array}

part A)

y-intercept is when the graph "intercepts" or touches the y-axis, and when that happens, x = 0, on that table, is the very first row, 0, 2700.

what does that mean? well, at 0 hours, the plane was 2700 miles away.
or another way to put it, the plane was still on the runway at the airport and hadn't taken off at 0 hours, and the airport where it was is 2700 miles away from its destination.

part B)

from the table, we can see the x = 1, y = 2160, and when x = 4, y = 540,
so our two points are (1, 2160) and (4, 540).

\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%   (a,b)&#10;&({{ 1}}\quad ,&{{ 2160}})\quad &#10;%   (c,d)&#10;&({{ 4}}\quad ,&{{ 540}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{540-2160}{4-1}\impliedby &#10;\begin{array}{llll}&#10;average\ rate\\&#10;of\ change&#10;\end{array}&#10;\\\\\\&#10;\cfrac{-1620}{3}\implies \boxed{-540}

or -540/1, well the top is the rise(miles) and the bottom is the run(hours)... so it means -540 miles per each 1hour,
or
for every passing hour the plane is travelling, the distance from its origin and its destination is shrinking, namely, is getting closer to its destination.

part C)

well, we know for every hour is dropping by 540, so, 4hrs is 540, so 5hours it will drop another 540, or 540 - 540 = 0

so, the domain will be [0, 5], since after 5hours it'd be at its destination, because at 5hrs the miles away is 0, meaning it arrived at the destination.
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3 years ago
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