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3 years ago

5

Select all the characteristics that will probably yield an ionic bond. Each answer refers to two atoms, Atom X and Atom Y. Atom

X is referred to first, and Atom Y is referred to second.
A.low E.N., low E.N.
B.high E.N., low E.N.
C.high E.N., high E.N.
D.low I.E., low I.E.
E.low I.E., high I.E.
F.high I.E., high I.E.

I can choose more than 1 answer.

2 answers:

Debora [2.8K]3 years ago

6 0

C high en high en is your answer

MariettaO [177]3 years ago

4 0

high E.N., low E.N.

low I.E., high I.E.

so, B and E

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How many atoms are in 490 moles of barium?

Usimov [2.4K]

Answer:

2.95 * 10^23 atoms

Explanation:

The number of atoms in a mole is always equal to <u>Avogadro's constant</u>, which is <u>6.02214076×10²³ mol⁻¹</u>.

To find the number of atoms in 0.490 moles of barium, multiply it with <u>Avogadro's constant</u>:

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Convert to SigFigs (if necessary):

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The compound cisplatin, pt(nh3)2cl2 , has been studied extensively as an antitumor agent.

Nataliya [291]

a. Elemental percent composition is the mass percent of each element in the compound.

The formula for mass elemental percent composition = $\frac{mass of element}{mass of compound}$ (1)

The molecular formula of cisplatin is $Pt(NH_3)_2Cl_2$ .

The atomic weight of the elements in cisplatin is:

Platinum, $Pt = 195.084 u$

Nitrogen, $N = 14.0067 u$

Hydrogen, $H = 1 u$

Chlorine, $Cl = 35.453 u$

The molar mass of $Pt(NH_3)_2Cl_2$ = $195.084+ (2\times 14.0067)+(6\times 1)+(2\times 35.453)$ = $300.00 g/mol$

The mass of each element calculated using formula (1):

- Platinum, $Pt$ %

$\frac{195.084}{300.00} \times 100 = 65.23$ %.

- Nitrogen, $N$ %

$\frac{2\times 14.0067}{300.00} \times 100 = 9.34$ %

- Hydrogen, $H$ %

$\frac{6\times 1}{300.00} \times 100 = 2.0$ %

- Chlorine, $Cl$ %

$\frac{2\times 35.453}{300.00} \times 100 = 23.63$ %

b. The given reaction of cisplatin is:

$K_2PtCl_4(aq)+2NH_3(aq)\rightarrow Pt(NH_3)_2Cl_2(s)+2KCl(aq)$

According to the balanced reaction, 1 mole of $K_2PtCl_4$ gives 1 mole of $Pt(NH_3)_2Cl_2$ .

Now, calculating the number of moles of $K_2PtCl_4$ in 100.0 g.

Number of moles = $\frac{given mass}{Molar mass}$

Molar mass of $K_2PtCl_4$ = $2\times 39.0983+195.084+4\times 35.453 = 415.093 g/mol$

Number of moles of $K_2PtCl_4$ = $\frac{100 g}{415.093 g/mol} = 0.241 mole$ .

Since, 1 mole of $K_2PtCl_4$ gives 1 mole of $Pt(NH_3)_2Cl_2$ . Therefore, mass of cisplatin is:

$0.241 mole\times 300 g/mol = 72.3 g$

For mass of $KCl$ :

Molar mass of $KCl$ = $39.0983 + 35.453 = 74.55 g/mol$

Since, 1 mole of $K_2PtCl_4$ gives 2 mole of $KCl$ . Therefore, mass of $KCl$ is:

$0.241 mole\times 74.55 g/mol\times 2 = 35.93 g$

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3 years ago

Find the volume of a gas at STP, if its volume is 80.0 mL at 109 kPa and -12.5°C.

exis [7]

Answer:

= 913.84 mL

Explanation:

Using the combined gas laws

P1V1/T1 = P2V2/T2

At standard temperature and pressure. the pressure is 10 kPa, while the temperature is 273 K.

V1 = 80.0 mL

P1 = 109 kPa

T1 = -12.5 + 273 = 260.5 K

P2 = 10 kPa

V2 = ?

T2 = 273 K

Therefore;

V2 = P1V1T2/P2T1

= (109 kPa × 80 mL × 273 K)/(10 kPa× 260.5 K)

<u>= 913.84 mL</u>

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0. Give an example of how an organism can use surface tension.<br><br><br>

Lady_Fox [76]

Answer:

In case of plants surface tension help to support the transpiration pull.

Explanation:

Surface tension is a force that hold the molecules in the surface to minimize the surface area.

During evaporation of excess amount of water from the stomata of leaves of plants by transpiration a surface tension is generated.

The generated surface tension helps to maintain the water column within the xylem tissue by the absorption of water from the soil by the roots.

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